Answer:
0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Step-by-step explanation:
Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.
First six not defective, each with 0.98 probability.
7th defective, with 0.02 probability. So

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
Find the expected number and variance of the number of components tested before a defective component is found.
Inverse binomial distribution, with 
Expected number before 1 defective(n = 1). So

Variance is:

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Answer:
1 ≤ n
Step-by-step explanation:
7−3n ≤ n+3
+3n +3n
7 ≤ 4n+3
-3 -3
4 ≤ 4n
divide by 4 on each side
1 ≤ n
This is what the graph would look like
Answer:
The price elasticity of demand is calculated as the percentage change in quantity divided by the percentage change in price.
Answer:
<h2>7n + 28</h2>
Step-by-step explanation:

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