Perimeter of a rectangle:
P=2I+2W=2(I+w)
But if the length and width of a rectangle are both double, then we would have:
Length=2I
width=2w
Therefore, its perimeter would be:
P=2(2I+2w)=4(I+w)
the old perimeter was P=2(I+w) and the new perimeter is P=4(I+w)=2[2(l+w)]
There the perimeter is twice as great.
Answer: C) the perimeter is twice as great.
Respuesta Es -3 (tried my best I’m only in Spanish two my main language is English)
Answer: 64.60
Step-by-step explanation:
lets do 6.80x9
= 61.20
for the half an hour, divide 6.80 by 2
it would be 3.40
61.20+3.40= 64.60