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2 years ago

What is the value of 5^4/5^6

Mathematics

2 answers:

Anuta_ua [19.1K]2 years ago

7 0

Answer:

1/25 or 0.04

Step-by-step explanation:

Elina [12.6K]2 years ago

3 0

Answer:

0.04

Step-by-step explanation:

5 to the 4th power (5 × 5 × 5 × 5) is 625.

5 to the 6th power (5 × 5 × 5 × 5 × 5 × 5) is 15625.

625/15625 = 0.04.

That's your answer!

Hope that helps and maybe earns a brainliest!

Have a great day! :)

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PLS HELP THIS IS LAST OF MY POINTS AND RUNNING OUT OF TIME. ANSWER ONLY IF U KNOW MATH.

ipn [44]

Answer:

using y=mx +c

c=0

m=y2-y2/x2-x1

m=16-0/2-0

m=8

y=8x+0

y=8x

hope that helped

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7 0

2 years ago

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24.. A toy company makes 40 plastic harmonicas in 30 minutes. At this

Dahasolnce [82]

Answer:

It will take 2 and a half hours

Step-by-step explanation:

Well 40 can go into 200 5 times so you would do 5 times 30 minutes which would be 150 minutes and then you would divide it by 60 to simplify which would be 2 hours and 30 minutes. So it will take 2 and a half hours to make 200 harmonicas.

200/40 = 5

5 * 30 = 150

150/60 = 2 hours and 30 minutes

3 0

2 years ago

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The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batterie

Fittoniya [83]

Answer:

The confidence interval is $25.16 < \mu < 26.85$

Step-by-step explanation:

From the question we are given a data set

25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

The mean of the this sample data is

$\= x = \frac{\sum x_i}{n}$

where is the sample size with values n = 10

$\= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}$

$\= x = 26$

The standard deviation is evaluated as

$\sigma = \sqrt{\frac{\sum (x-\= x)}{n} }$

substituting values

$= \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }$

$\cdot \ \cdot \ \cdot \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }$

$\sigma = 1.625$

The confidence level is given as 90% hence the level of significance is calculated as

$\alpha = 100 -90$

$\alpha =10$ %

$\alpha = 0.10$

Now the critical values of $\frac{\alpha }{2}$ is obtained from the normal distribution table as

$Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining the critical values of $\frac{\alpha }{2}$ instead of $\alpha$ is because we are considering two tails of the area under the normal curve