Ask question

Ask question

All categories

marshall27 [118]

3 years ago

12

A carpenter is building a rectangular fence for a playground. One side of the playground is the wall of a building 70 ft. wide.

He plans to use 340 feet of fencing maerial what is the length of the playground if the width is 70ft

1 answer:

tangare [24]3 years ago

8 0

Answer:

sorry , but where is the question?

You might be interested in

Which expression is equivalent to (64 y Superscript 100 Baseline) Superscript one-half?

Alex_Xolod [135]

Answer:

$8y^{50}$

Step-by-step explanation:

This expression is equal :

${(64y^{100})}^{\frac{1}{2}}$

Here we can use this rule :

$(a^mb^n)^y=a^{my}b^{ny}$

Now, 64 we can write like : $8^2$

$(8^2y^{100})^{\frac{1}{2}}$

Now we can use our rule :

$8^{2*\frac{1}{2}}y^{100*\frac{1}{2}$

When we simplify, we have :

8y^{50}

6 0

4 years ago

Read 2 more answers

A certain animated movie earned $ 1 . 1 ? 1 0 9 $1.1?10 9 in revenues at the box office. The movie lasts 9 . 1 ? 1 0 1 9.1?10 1

Leokris [45]

Answer:

$ $1.21\times 10^{7}$ per minute.

Step-by-step explanation:

We have been given that a certain animated movie earned $ $1.1\times10^{9}$ in revenues at the box office. The movie lasts $9.1\times10^{1}$ minutes.

To find the revenue earned per minute of the movie we will will divide $1.1\times10^{9}$ by $9.1\times10^{1}$ .

$\text{The revenue earned per minute by the movie}=\frac{1.1*10^{9}}{9.1*10^{1}}$

Using quotient rule of exponents we will get,

$\text{The revenue earned per minute by the movie}=\frac{1.1}{9.1}*10^{(9-1)}$

$\text{The revenue earned per minute by the movie}=\frac{1.1}{9.1}*10^{8}$

$\text{The revenue earned per minute by the movie}=0.1208791208791209\times 10^{8}$

We can write 0.1208791208791209 as $1.208791208791209\times10^{-1}$ .

$\text{The revenue earned per minute by the movie}=1.208791208791209\times 10^{-1} \times 10^{8}$

Using product rule of exponents we will get,

$\text{The revenue earned per minute by the movie}=1.208791208791209\times 10^{-1+8}$

$\text{The revenue earned per minute by the movie}=1.208791208791209\times 10^{7}$

Upon rounding our answer to two decimal places we will get,

$\text{The revenue earned per minute by the movie}=1.21\times 10^{7}$

Therefore, the movie had earned a revenue of $ $1.21\times 10^{7}$ per minute.

7 0

3 years ago

Read 2 more answers

Which relationship describes angles 1 and 2?

jasenka [17]

Answer:

vertical

Step-by-step explanation:

just vertical

7 0

3 years ago

Please help with question 11! BRAINLIEST to correct answer!!

Contact [7]

Answer:

No

Step-by-step explanation:

you can see that they can not go into each other and come out correct so the answer would have to be no (we were working on this same thing)

3 0

3 years ago

Read 2 more answers

Find the area of triangle ABC with vertices A(2,1), B (12,2), C (12,8). Hence, or otherwise find the perpendicular distance from

Lapatulllka [165]

<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$ </h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

$x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and y_3=8$

The area of a triangle is= $\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]$

= $|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|$

= $|-54|$ = 54 square units

The length of AC = $\sqrt{(x_1-x_3)^{2} +(y_1-y_3)^2}$

= $\sqrt{(2-12)^{2} +(1-8)^2}$

= $\sqrt{149}$ units

Let the perpendicular distance from B to AC be = x

According To Problem

$\frac{1}{2} \times x \times \sqrt{149} = 54$

⇔ $x =\frac{108}{\sqrt{149} }$ units

Therefore the perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$

5 0

3 years ago