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Vilka [71]
3 years ago
7

the population of a large Is city is 2,707,210 write this number in scientific notation to the nearest thousands​

Mathematics
1 answer:
kotegsom [21]3 years ago
8 0

Answer:

2.70721×10^(6)

Step-by-step explanation:

There is always comma at the end, bring the comma near to (2) multiply 10, put the power of 10 based to the digits, after 2 it have 6 digit so the power of 10 is 6.

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In 2008, data from the Center for Disease Control revealed that 28.5% of all male teenagers, aged 18-19 and attending U.S. colle
m_a_m_a [10]

Answer:

a) H0 : u = 28.5%

H1 : u < 28.5%

b) critical value = - 1.645

c) test statistic Z= - 1.41

d) Fail to reject H0

e) There is not enough evidence to support the professor's claim.

Step-by-step explanation:

Given:

P = 28.5% ≈ 0.285

X = 210

n = 800

p' = \frac{X}{n} = \frac{210}{800} = 0.2625

Level of significance = 0.05

a) The null and alternative hypotheses are:

H0 : u = 28.5%

H1 : u < 28.5%

b) Given a 0.05 significance level.

This is a left tailed test.

The critical value =

-Z_0.05 = -1.645

The critical value = -1.645

c) Calculating the test statistic, we have:

Z = \frac{p' - P}{\sqrt{\frac{P(1-P)}{n}}}

Z = \frac{0.2625 - 0.285}{\sqrt{\frac{28.5(1-28.5)}{800}}}

Z = -1.41

d) Decision:

We fail to reject null hypothesis H0, since Z = -1.41 is not in the rejection region, <1.645

e) There is not enough evidence to support the professor's claim that the proportion of obese male teenagers decreased.

5 0
3 years ago
Match the function with the graph
Daniel [21]
The answer is B because it’s not a straight line and x can not have an exponent of 2 bc it will make it nonlinear
5 0
3 years ago
Apply the​ 68-95-99.7 rule to answer the question. The lifetimes of light bulbs of a particular type are normally distributed wi
Montano1993 [528]

Answer:

95%.

Step-by-step explanation:

We have been given that the lifetimes of light bulbs of a particular type are normally distributed with a mean of 370 hours and a standard deviation of 7 hours.

We are asked to find the percentage of the bulbs whose lifetimes lie within 2 standard deviations to either side of the​ mean using empirical rule.

The empirical rule (68-95-99.7) states that approximately 68% of data points lie within 1 standard deviation of mean and 95% of data points lie within two standard deviation of mean. 99.7% of data points lie within three standard deviation of mean.

Therefore, approximately 95% of data points lie within two standard deviation of mean.

7 0
3 years ago
An amusement park ride rotates around a fixed axis such that the angular position of a point on the ride follows the equation: θ
pshichka [43]
I found a missing question online. <span>What is the magnitude of the angular displacement of the ride in radians between times t=0 and t= t1?
We can imagine our ride traveling from the starting point A to some point B (at t=1s).
We can find the angle of both points, and when we subtract them we get angular displacement.
</span>A: \theta(0)=a\\&#10;B: \theta(1)=a+b(1)^2-c(1)^3=a+b-c
<span>Our angular displacement is:
</span>\Delta\theta=\theta(1)-\theta(0)=a+b-c-a=b-c=0.85-0.035=0.815 rad<span>


</span>
8 0
3 years ago
Consider the line segment below that is five feet long. Is Q the midpoint of PR? Justify your answer.
givi [52]

Answer:

Q is not the midpoint of PR

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If Q is the midpoint of PR

then

PQ=QR

substitute the given values and solve for x

15x-2=5x+3\\15x-5x=3+2\\10x=5\\x=0.5

Remember that

PR=5\ ft ----> given problem

PR=PQ+QR\\PR=(15x-2)+(5x+3)

substitute the value of x

PR=(15(0.5)-2)+(5(0.5)+3)

PR=(5.5)+(5.5)

PR=11\ ft

Compare with the given value of PR

5\ ft\neq 11\ ft

therefore

Q is not the midpoint of PR

4 0
3 years ago
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