Answer:
No, it is not a linear equation
Step-by-step explanation:
This equation contains the term x², meaning that it is a quadratic function (parabola)
So, it is not a linear equation.
If it were a linear equation, x would not be squared, and the equation would have been in y = mx + b form.
The answer is no, it is not a linear equation.
Answer:
d. Twenty-five cars are randomly selected with the new transmission and 25 with the old transmission.
Step-by-step explanation:
A hypothesis test on the difference between the means must satisfy the following conditions
1) the samples must be randomly selected
2) each sample must have a known standard deviation
3) the samples must be independent
4) the samples must be from normal distribution
Hence only part d gives the right answer.
Use the compound amount formula:
$2,300 = P(1+0.02)^3. Solve this for P:
P = $2,300 / (1.02)^3 = $2167.34.
By depositing $2,167.34 now, Cheryl would have $$2300 after three years.
It's a trick question. There are an infinite number of mixed numbers between 3 and 4 that can multiply to equal 12 (for example, 3 and 3/7 times 3 and 1/2), but there are no mixed numbers between 3 and 4 that can multiply to equal 9. 3 times 3 is not between them but is 3, but that quantity is excluded because 3<x<4. Anything even a small bit above the number 3 would have to be multiplied by 2 and some fraction, which would not be between 3 and 4.
The original expression is equal to 0 because anything multiplied by 0 is equal to 0. Solve inside the brackets for the possible answer choices to find what will equal 0.
Start with the first expression. Add 4 and negative 4 will become 0, and -1 times 0 is equal to 0. Let's solve for the others just to be sure.
In the second expression, solving inside the brackets gives you 8. -1 times 8 is equal to -8.
Adding 4 and negative 4 in the third expression leaves you with 0. But, 1 + 0 is equal to 1.
Adding negative 4 and negative 4 gives you the answer of -8, and -1 times -8 is equal to 8.
Your answer is the first expression, or A.
