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Dmitry [639]
3 years ago
11

NEED HELP ASAP WILL MARK BRAINLIEST

Mathematics
1 answer:
kow [346]3 years ago
6 0

Answer:

r segment

Step-by-step explanation:

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Yu-Jun's craft store sells 3 handmade
Alekssandra [29.7K]

Answer:

C =3.33x

Step-by-step explanation:

The cost of 1 barrette is

9.99/3  sine it is 9.99 for 3 barrettes

or 3.33 per barrette

We want x barrettes

or 3.33*x

C is the total cost

C =3.33x

4 0
3 years ago
1/4 BEFORE 7:00 is 6:___? (my parents are giving me hard times rn and i hate it)
bagirrra123 [75]

Answer:

That sucks that your parents are stressing u out. i hope it gets better.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Jamal simplified ...
brilliants [131]
\bf \sqrt{75x^5y^8}\qquad 
\begin{cases}
75=3\cdot 25\\
\qquad 3\cdot 5^2\\
x^5=x^{4+1}\\
\qquad x^4x^1\\
\qquad (x^2)^2x\\
y^8=y^{4\cdot 2}\\
\qquad (y^4)^2
\end{cases}\implies \sqrt{3\cdot 5^2\cdot (x^2)^2x(y^4)^2}
\\\\\\
5x^2y^4\sqrt{3x}
4 0
2 years ago
What is the answer for this question-7x-2y=-13
Gala2k [10]
What are you trying to find? y?x?..???
5 0
2 years ago
For a certain​ candy, 15​% of the pieces are​ yellow, 1010​% are​ red, 2020​% are​ blue, 55​% are​ green, and the rest are brown
MatroZZZ [7]
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.

Explanation:
A) The probability that it is brown is the percentage of brown we have.  Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%.  The probability that one drawn is yellow or blue would be the two percentages added together:  15+20 = 35%.  The probability that it is not green would be the percentage of green subtracted from 100:  100-5=95%.  Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events.  All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.  
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.

The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:

0.85^3 = 0.614 = 61.4%.

The probability that at least one is green is computed by subtracting 1-(probability of no green).  We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
3 0
3 years ago
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