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babymother [125]
3 years ago
7

What are the factors of 3x2 + 10x + 3? (3x − 1)(x − 3) (3x − 3)(x − 1) (3x + 1)(x + 3) (3x + 3)(x + 1)

Mathematics
2 answers:
natka813 [3]3 years ago
4 0
The factors of 3x^2+10x+3 are (3x+1)(x+3)
finlep [7]3 years ago
3 0

Answer:

(3x+1)(x+3)

Step-by-step explanation:

We have been given an expression 3x^2+10x+3. We are asked to factor the given expression.

We will factor our given expression by splitting the middle term. We need two numbers which add up-to 10 and whose product is 9.

We know that 1 and 9 are such numbers.

3x^2+9x+1x+3

Make two groups:

(3x^2+9x)+(1x+3)

3x(x+3)+1(x+3)

(3x+1)(x+3)

Therefore, our required factors are (3x+1)(x+3) .

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Suppose Richard walks 1 kilometer every 10 minutes. How many meters further can he walk in 1 hour at this new rate?
Andrej [43]
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1 kilometer : 10 minutes

That would mean 

6 kilometers : 60 minutes

<span>Hope that helps and correct me if I'm wrong!</span>
5 0
3 years ago
Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
a line is perpendicular to y = 3/7x - 2 and intersects the point (3,3). What is the equation of this perpendicular line?
snow_lady [41]

Answer:

y = -7/3x + 10

Step-by-step explanation:

Step 1: Find the slope of the perpendicular line

Do this by taking the negative inverse of the first line

m = -7/3

Step 2: Find <em>b</em>

y = mx + b

y = -7/3x + b

3 = -7/3(3) + b

3 = -7 + b

b = 10

You should get y = -7/3x + 10 as your final answer.

6 0
3 years ago
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