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Ulleksa [173]
3 years ago
14

In a factory A, about 3 out of every 2,000 toys have a defect. In factory B, about 5 out of every 4,500 toys have a defect. One

week, each factory produced 18,000 toys. Which factory had the greater number of toys with defects? Solve. Use a proportion to solve.
Mathematics
1 answer:
gavmur [86]3 years ago
7 0

Answer:

27

Step-by-step explanation:

Factory A proportion:

3 : 2,000

Factory B proportion:

5 : 4,500 (this can be simplified):

1 : 900

Now plug in 18,000 to each proportion:

Factory A:

x : 18,000

3 : 2,000

x = 27

Factory B:

x : 18,000

1 : 900

x = 20

Factory A had the greater amount of defects, 27

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Answer:

f(x)=4x

Step-by-step explanation:

Given: See the attached image

To find: the function represented by the table

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Here, -2,-1,0,1 are elements in the domain and -8,-4,0,4 are elements in the co-domain.

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Download docx
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