In a factory A, about 3 out of every 2,000 toys have a defect. In factory B, about 5 out of every 4,500 toys have a defect. One
week, each factory produced 18,000 toys. Which factory had the greater number of toys with defects? Solve. Use a proportion to solve.
1 answer:
Answer:
27
Step-by-step explanation:
Factory A proportion:
3 : 2,000
Factory B proportion:
5 : 4,500 (this can be simplified):
1 : 900
Now plug in 18,000 to each proportion:
Factory A:
x : 18,000
3 : 2,000
x = 27
Factory B:
x : 18,000
1 : 900
x = 20
Factory A had the greater amount of defects, 27
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