Answer:
Step-by-step explanation:Since we want to know how much time elapsed since the object was launched until it ht the ground. At the ground, the height is 0.
Therefore the equation h(t) = 80t – 16t2 becomes 0= 80t – 16t2
Solving the equation for t gives 80t =16t2 or 16t=80 or t=5sec
The object hits the ground 5 seconds after it is launched.
The answer is the first page, first graph
F(x) = x^5 - 1; g(x) = 5x^2; h(x) = 2x
Answer:
Multiply the expressions.
90
x
3
−
129
x
2
+
13
x
+
22