All categories

3 years ago

72 is what percent of 160?

Mathematics

2 answers:

Alchen [17]3 years ago

5 0

72/160=?

Divide 72 by 160 to find the percent.

72/160=0.45

72 is 45% of 160.

I hope this helps :)

dem82 [27]3 years ago

4 0

72 is 45% of 160. I'm 100% positive about it

You might be interested in

When price increases, quantity supplied:

lara31 [8.8K]

It should increase but I’m between stays the same or increase, I’m not sure in a 100% sorry...

3 0

3 years ago

On a certain standardized test used for college entrance purposes, the mean score was 21 and the standard deviation was 5. The d

Fiesta28 [93]

Answer:

Step-by-step explanation:

Carlos' score was 2 standard deviations from the mean, so his z-score was 2.0. You can either use the empirical 68-95-98.5 rule, or you can plug it into your calculator as normalcdf(-999, 2) = .977

So 97.7% of people had a score lower than Carlos!

.977 * 1.5 million = 1,465,500 people

5 0

3 years ago

Someone plz help me :(

saul85 [17]

the answer is A

hope this helps

4 0

3 years ago

Read 2 more answers

Determine whether the pair of lines is parallel, perpendicular, or neither. Y=-6/5x+2 Y=6/5x+2

max2010maxim [7]

$k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1\cdot m_2=-1\\\\k\ ||\ l\iff m_1=m_2$

$k:y=-\dfrac{6}{5}x+2\to m_1=-\dfrac{6}{5}\\\\l:y=\dfrac{6}{5}x+2\to m_2=\dfrac{6}{5}\\\\m_1\neq m_2\to\text{no parallel}\\\\m_1\cdot m_2=-\dfrac{6}{5}\cdot\dfrac{6}{5}\neq-1\to\text{ no perpendicular}$

Answer: NEITHER

4 0

3 years ago

The line on the graph passes through to points A (1, 3) B (7, 1)

Flura [38]

Answer:

a. Gradient of line AB is $-\frac{1}{3}$

b. The gradient of a line perpendicular to line AB is 3

c. The equation of a line passing through point (4,2) and perpendicular to AB is $y = 3x - 10$

Step-by-step explanation:

Given

Point A (1, 3) B (7, 1)

Required

Gradient of AB

Gradient of a line is represented by m

m is calculated using the following formula

$m = \frac{y_{2} - y_{1} }{x_{2} - x_{1}}$

Where the general representation of the coordinates are $A(x_1,y_1) and B(x_2,y_2)$

From the given data, we have that

$A(x_1,y_1) = A(1,3)$

$B(x_2,y_2) = A(7,1)$

So, from there we know that

$x_1 = 1;y_1 =3; x_2 = 7;y_2 =1$

$m = \frac{y_{2} - y_{1} }{x_{2} - x_{1}}$ becomes

$m = \frac{1 - 3}{7 - 1}$

$m = \frac{-2}{6}$

$m = -\frac{1}{3}$

Required

Find the gradient of a line perpendicular to AB

Recall that gradient of a line is represented by m

The condition for perpendicularity is that $m_1.m_2 = -1$

In (a) above, we solved the gradient of line AB to be $-\frac{1}{3}$

Let $m_1$ represent gradient of line AB

Hence, $m_1 = -\frac{1}{3}$

Substitute $-\frac{1}{3}$ for $m_1$ in $m_1.m_2 = -1$

This will give

$\frac{-1}{3} * m_2 = -1$

Multiply both sides by -3

$-3 * \frac{-1}{3} * m_2 = -1 * -3$

$m_2 = -1 * -3$

$m_2 = 3$

Hence, the gradient of a line perpendicular to line AB is 3

Required

Find the equation of a line passing through point (4,2) and perpendicular to AB

Equation is calculated using the gradient formula

$m = \frac{y_{2} - y_{1} }{x_{2} - x_{1}}$

Since only one point is known, the formula is represented as follows

$m = \frac{y - y_{1} }{x - x_{1}}$

Where $x_1 = 4; y_1 = 2$

Since, the line is perpendicular to line AB, then its gradient m is equal to 3 (as calculated in b above)

So, we have $x_1 = 4; y_1 = 2; m = 3$

By substitution

$m = \frac{y - y_{1} }{x - x_{1}}$ becomes

$3 = \frac{y - 2}{x - 4}$

Multiply both sides by x - 4

$3 * (x - 4) = \frac{y - 2}{x - 4} * (x - 4)$

$3(x - 4) = {y - 2}$

Open brackets

$3x - 12 = y - 2$

Make y the subject of formula

$3x - 12 + 2= y$

$3x - 10 = y$

Reorder

$y = 3x - 10$

Hence, the equation of a line passing through point (4,2) and perpendicular to AB is $y = 3x - 10$

3 0

3 years ago