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4 years ago

11

What is the area of the parallelogram 4cm 5cm 9cm

2 answers:

Alenkasestr [34]4 years ago

6 0

Answer:

Step-by-step explanation:

180

Ganezh [65]4 years ago

3 0

Answer:

180

Step-by-step explanation:

You might be interested in

An aircraft manufacturer wants to determine the best selling price for a new airplane. The company estimates that the initial co

Blizzard [7]

Answer:

$(a)$ $C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2$

$p(x)=320-7.7p$

$R(x)=(320-7.7p)p=320p-7.7p^2$

$(b)$ $x=82 \text{planes}$

$(c)$ $p=\$30.91 M\;\; \text{per plane}$

$(d)$ maximum profit $=\$ 15.90M$

Step-by-step explanation:

Given that,

The company estimates that the initial cost of designing the aeroplane and setting up the factories in which to build it will be 500 million dollars.

The additional cost of manufacturing each plane can be modelled by the function.

$m(x)=20x-5x^{\frac{3}{4}}+0.01x^2$

$(a)$ Find the cost, demand (or price), and revenue functions.

$C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2$

$p(x)=320-7.7p$

$R(x)=(320-7.7p)p=320p-7.7p^2$

$(b)$ Find the production level that maximizes profit.

$f=R(x)-C(x)$

$\Rightarrow f=320p-7.7p^2-(500+20x-5x^{\frac{3}{4}}+0.01x^2)$

$\Rightarrow df=320dp-15.4pdp-20dx+5(\frac{3}{4} )x^{\frac{-1}{4} }dx-0.02xdx$

$x=320-7.7p$

$p=\frac{320-x}{7.7}$

$\frac{dp}{dx} = \frac{-1}{7.7}$

$\frac{df}{dx}=\frac{320}{-7.7} -\frac{15.4(320-x) }{7.7(\frac{-1}{7.7} )}-20+5\frac{3}{4} x^{\frac{-1}{4}} -0.02x=0$

$\Rightarrow -41.5584+83.1169-0.2597x-20+3.75x^{\frac{-1}{4} }-0.02x=0$

$\Rightarrow 21.5585+3.75x^{\frac{-1}{4} }-0.279x=0$

$\Rightarrow x=82 \text{planes}$

$(c)$ Find the associated selling price of the aircraft that maximizes profit.

$p=\frac{320-82}{7.7}$

$\Rightarrow p=\$30.91 M\;\; \text{per plane}$

$(d)$ Find the maximum profit.

Manufacturing cost of one plane is:

$m(1)=20-5+0.01$

$=\$15.01 M$

maximum profit $=\$(30.91-15.01)M$

$=\$15.90M$

3 0

3 years ago

The sum of two times a number and 11 is negative 7

slavikrds [6]

|2 • x| + 11 = -7
x = -9

4 0

4 years ago

Read 2 more answers

The pairs of numbers below represent the price of different

Ymorist [56]

Answer:

Option C: 2 books for $14, 5 books for $35

Step-by-step explanation:

A proportional relationship between two quantities would always have a constant of proportionality. Thus,

Constant of proportionality, k = y/x

In this case,

x = quantity of books

y = price

Let's see which pair will have a constant of proportionality:

Option A: 4 books for $24,8 books for $40

24/4 = 6;

40/8 = 5.

No constant of proportionality.

Option B: 5 books for $25, 6 books for $36

25/5 = 5

36/6 = 6

No constant of proportionality.

Option C: 2 books for $14, 5 books for $35

14/2 = 7

35/5 = 7

Constant of proportionality, k = 7.

This pair represents a proportional relationship.

Option D: 3 books for $15, 7 books for $28

15/3 = 5

28/7 = 4

No constant of proportionality.

4 0

3 years ago

storchak [24]

Question:

Lisa walks at an average speed of 6 km/h for 15 hours.

Dan completes the same distance in an hour. Calculate Dan's average speed.

Answer:

$Speed = 90km/hr$

Step-by-step explanation:

Given

Lisa:

$Speed = 6km/hr$

$Time = 15\ hr$

First, we calculate the distance covered by Lisa:

$Distance = Speed * Time$

$Distance = 6km/hr * 15\ hr$

$Distance = 90km$

So, Dan distance can be represented as:

$Distance = 90km$ --- Dan completes the same distance as Lisa

$Time = 1\ hr$ -- Time to complete the distance

Dan's average speed is:

$Speed = \frac{Distance}{Time}$

$Speed = \frac{90km}{1\ hr}$

$Speed = 90km/hr$

<em>Hence, Dan's average speed is 90km/hr</em>

4 0

3 years ago

What would be the equation of the cannonball’s path if it was launched with the same velocity, but from the ground instead?

natita [175]

The quadratic equation cannonball’s path if it was launched with the same velocity, but from the ground instead would be given by:

$h(t) = -4.9t^2 + 19.8t$

<h3>What is the quadratic equation for the height of a projectile?</h3>

Considering the gravity, it is modeled by:

$h(t) = -4.9t^2 + v_0t + h_0$

In which:

$v_0$ is the initial velocity.

$h_0$ is the initial height.

For this problem, we want:

The same initial velocity, hence $v_0 = 19.8$ .

Launched from the ground, hence $h_0 = 0$ .

Then, the equation is:

$h(t) = -4.9t^2 + 19.8t$

More can be learned about quadratic equations at brainly.com/question/24737967

3 0

3 years ago