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3 years ago

9

Find the value of X. (and the rest)

1 answer:

lianna [129]3 years ago

8 0

Answer:

a=70

b=110

c=50

d=130

e=50

Step-by-step explanation:

these are just angle properties

a=70

b=110

c=50

d=130

e=50

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Cheryl and rodney are mixing yellow and blue paint to make green paint. The table shows how much of each color they use. Whose g

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The amount of blue color in the green paint is an illustration of ratios and proportions.

Cheryl's green paint has more blue color

The proportion of blue color is calculated as:

$\mathbf{Proportion = \frac{Blue}{Blue+ Yellow}}$

So, we have:

$\mathbf{Cheryl= \frac{16}{16+ 24}}$

$\mathbf{Cheryl= \frac{16}{40}}$

$\mathbf{Cheryl= 0.40}$

Express as percentage

$\mathbf{Cheryl= 40\%}$

$\mathbf{Rodney= \frac{6}{6+ 10}}$

$\mathbf{Rodney= \frac{6}{16}}$

$\mathbf{Rodney= 0.375}$

Express as percentage

$\mathbf{Rodney= 37.5\%}$

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Read more about proportions at:

brainly.com/question/21126582

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2 years ago

What is 5 less than the product of 10 and c?

Finger [1]

Hi, the equation you typed is 10c-5

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2 years ago

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

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3 years ago

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2 years ago

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