Answer:
The correct option is D) (5x − 2)(2x − 3).
Step-by-step explanation:
Consider the provided expression.
Where x is time in minutes.
We need to find the appropriate form of the expression that would reveal the time in minutes when the trough is empty.
When the trough is empty the whole expression becomes equal to 0.
Substitute the whole expression equal to 0 and solve for x that will gives us the required expression.
Now consider the provided option.
By comparison the required expression is D) (5x − 2)(2x − 3).
Hence, the correct option is D) (5x − 2)(2x − 3).
Answer:
4 movies, $20
Step-by-step explanation:
Given data
Family Video
charges $10 for a monthly membership and
$2.50 per movie
let the number of movies be x
and the charge for x movies be y
y= 10+2.5x----------1
Babe's Movies
charges a $12
membership and $2 per
movie.
let the number of movies be x
and the charge for x movies be y
y= 12+2x----------2
equate 1 and 2
10+2.5x= 12+2x
collect like terms
12-10= 2.5x-2x
2= 0.5x
x= 2/0.5
x= 4 movies
put x= 4 in equation 1 or 2
y= 12+2x----------2
y= 12+2*4
y= 12+8
y= $20
3(3x+8)=4(2x+8)
9x+24=8x+32
x=8
2(8)=16
3(8)=24
that means that the younger brother is 16 years old
![[Hello,BrainlyUser!\; I'm\;Lenvy]](https://tex.z-dn.net/?f=%5BHello%2CBrainlyUser%21%5C%3B%20I%27m%5C%3BLenvy%5D)
Answer:
42 feet
Step-by-step explanation:
First let know what is
Yards to Feet
Note that;
1 Yard ⇒ 3 Feet
Thus, Formula: Multiply the length value by 3
Given:
Lena bought 14 yards of ribbon. How many feet of ribbon did she buy?
Therefore, 14 * 3 = 42
Hence, Answer is Lena brough 42 feet of ribbon.
~[CloudBreeze]~
Answer:
The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.
Step-by-step explanation:
According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.
Then, the mean of the distribution of sample mean is given by,
And the standard deviation of the distribution of sample mean is given by,
The information provided is:
<em>μ</em> = 144 mm
<em>σ</em> = 7 mm
<em>n</em> = 50.
Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.
Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:
*Use a <em>z</em>-table for the probability.
Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.
