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salantis [7]
2 years ago
8

Write an equation of a line in point-slope form that passes through (-4,-7) and has a slope of -2

Mathematics
1 answer:
xeze [42]2 years ago
8 0
\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})
\qquad \qquad \qquad 
% slope  = m
slope =  m\implies -2
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-7)=-2[x-(-4)]
\\\\\\
y+7=-2(x+4)
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Giving brainlist to whoever answers
Nookie1986 [14]

Answer:

7/12

Step-by-step explanation:

lemon is 5/12

lime is 7/12

6 0
2 years ago
The answers are either: 12, 2, 8, or 10 please helppp
blsea [12.9K]

Answer: 10 I believe

Step-by-step explanation:

3 0
3 years ago
Help?<br><br> a) 2/10 + 8/100<br> b) 13/100 + 4/10<br> c) 6/10 + 39/100<br> D) 70/100 + 3/10
Leni [432]

\green{––––––––––––––––––––––––––––––}

\huge\red{\boxed{\tt{{«ANSWER»}}}}

  • A) 2/10 + 8/100 = <u>0</u><u>.</u><u>2</u><u>8</u>
  • B) 13/100 + 4/10 = <u>0</u><u>.</u><u>5</u><u>3</u>
  • C) 6/10 + 39/100 = <u>0</u><u>.</u><u>9</u><u>9</u>
  • D) 70/100 + 3/10 = <u>1</u>

<u>\green{––––––––––––––––––––––––––––––}</u>

<em><u>#</u></em><em><u>carry </u></em><em><u>on </u></em><em><u>learning </u></em><u><</u><u>3</u>

5 0
2 years ago
Math help.... Please....
garri49 [273]
First, you want to solve for the equation for this problem, would be: 
0.05N + 0.10D = 20.50 
While N = The amount of nickels, and D = The amount of dimes. 

Since N = 164, and D = 123. It would add up to 287 coins. 164 + 123 = 287. 
Now that you have the number for those two variables, solve the equation for when N = 164, and D = 123. 
0.05N + 0.10D = 20.50 
<span>0.05(164) + 0.10(123) = 20.50 
</span><span>8.2 + 12.3 = 20.50 
</span>20.50 = 20.50 
So, there is 164 nickels, and 123 dimes for your answer. 

<em>I hope this helps! </em>

<em>~ Notorious Sovereign</em>
6 0
3 years ago
Read 2 more answers
Please help!!!! will mark brainlest
fomenos

Answer: B. 84 in²

Step-by-step explanation:

Divide the area into two regions: a rectangle and a trapezoid (depicted in the attached photo).

Find the area of the rectangle:

Area of a rectangle=length*width

Area of rectangle=(5 in)( 10 in)

Area of rectangle=50 in²

Next, calculate the area of the trapezoid:

Area of trapezoid=\frac{h(b_{1} +b_{2}) }{2}

h=10 in-6 in

h=4 in

b_{1} =15 in

b_{2} =15 in-5 in

b_{2} =10 in

Area of trapezoid=\frac{4in(7 in+10in)}{2}

Area of trapezoid=\frac{4(17in^{2})  }{2}

Area of trapezoid=\frac{68in^{2} }{2}

Area of trapezoid=34in^{2}

Add the area of the trapezoid to the area of the rectangle to find the total area: 50 in²+34 in²=84 in²

3 0
2 years ago
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