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3 years ago

9

Enrollment is the ski/snowboard club increase by 30 percent this year. there are now 182 students in this club how many students

were there last year

1 answer:

lbvjy [14]3 years ago

7 0

127 students were in the club last year

You might be interested in

45 is 60% percent of what number

trasher [3.6K]

The answer is 75 as you would divide 45 by 0.6

5 0

3 years ago

Help please! Geometry word problem!

mr Goodwill [35]

By applying <em>reflection</em> theory and constructing a <em>geometric</em> system of two <em>proportional right</em> triangles, the height of the stainless steel globe is approximately 140 ft.

<h3>How to estimate the height of the stainless steel globe</h3>

By physics we know that both the angle of incidence and the angle of reflection are same. Thus, we have a <em>geometric</em> system formed by two <em>proportional right</em> triangles:

5.6 ft / 4 ft = h / 100 ft

h = (5.6 ft × 100 ft) / 4ft

h = 140 ft

By applying <em>reflection</em> theory and constructing a <em>geometric</em> system of two <em>proportional right</em> triangles, the height of the stainless steel globe is approximately 140 ft.

To learn more on geometry: brainly.com/question/16836548

#SPJ1

8 0

2 years ago

Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind

Gemiola [76]

Answer:

(a)

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

(b)

i.

$1\ girl = \{GBB, BBG, BGB\}$

$P(1\ girl) = 0.375$

ii.

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

$P(Atleast\ 2 \ girls) = 0.5$

iii.

$No\ girl = \{BBB\}$

$P(No\ girl) = 0.125$

Step-by-step explanation:

Given

$Children = 3$

$B = Boys$

$G = Girls$

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

And the number of elements are:

$n(S) = 8$

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

$1\ girl = \{GBB, BBG, BGB\}$

And the number of the list is;

$n(1\ girl) = 3$

The probability is calculated as;

$P(1\ girl) = \frac{n(1\ girl)}{n(S)}$

$P(1\ girl) = \frac{3}{8}$

$P(1\ girl) = 0.375$

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

And the number of the list is;

$n(Atleast\ 2 \ girls) = 4$

The probability is calculated as;

$P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}$

$P(Atleast\ 2 \ girls) = \frac{4}{8}$

$P(Atleast\ 2 \ girls) = 0.5$

Solving (biii) No girl

From the list of possible elements, we have:

$No\ girl = \{BBB\}$

And the number of the list is;

$n(No\ girl) = 1$

The probability is calculated as;

$P(No\ girl) = \frac{n(No\ girl)}{n(S)}$

$P(No\ girl) = \frac{1}{8}$

$P(No\ girl) = 0.125$

7 0

3 years ago

0f the 64 students in grade five, 3/8 of them either walk or ride a bike to school. The rest take a bus. How many fifth graders

UkoKoshka [18]

40 fifth graders take a bus to school. 8x8= 64 so they have you a good fraction to start with to find out how many kids are walking or taking their bike (3/8) all you have to do is multiply 3 and 8 which equals 24 to find the fraction of the amount of kids who take the bus you subtract 3 from 8 which gives 5/8 and to get the answer you multiply 5 and 8 which is 40.

3 0

3 years ago

1.) A 20° sector in a circle has an area of 21.5π yd².

a_sh-v [17]

<u>Part 1)</u> A 20° sector in a circle has an area of 21.5π yd².

What is the area of the circle?

we know that

the area of a circle represent a sector of $360$ degrees

so by proportion

$\frac{21.5\pi }{20} =\frac{x}{360} \\ \\ x*20=360*21.5\pi \\ \\x=(360*21.5*3.14)/20\\ \\x= 1,215.18\ yd^{2}$

therefore

<u>the answer part 1) is</u>

The area of the circle is $1,215.18\ yd^{2}$

<u>Part 2)</u> What is the area of a sector with a central angle of 3π/5 radians and a diameter of 21.2 cm?

we know that

the area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

in this problem we have

$Diameter=21.2\ cm\\ r=Diameter/2\\r=21.2/2\\r= 10.6\ cm$

<u>Find the area of the circle</u>

$A=\pi r^{2}$

$A=\pi*10.6^{2}$

$A=352.8104\ cm^{2}$

<u>Find the area of the sector</u>

we know that the area of the circle represent a sector of $2\pi$ radians

by proportion

$\frac{352.8104}{2\pi }=\frac{x}{(3\pi/5)} \\\\x*2\pi=(3\pi*352.8104)/5\\ \\x= 105.84\ cm^{2}$

therefore

<u>the answer part 2) is</u>

the area of the sector is

$105.84\ cm^{2}$

7 0

3 years ago