She made 3 sandwiches because 5-2 3/4 = 2 1/4.
2 1/4 as an improper fraction=(4*2)+1=9/4
9/4 / 3/4=3.
You have that situation with ANY base that's less than ' 1 '.
Examples:
(0.9)² = 0.81 (90% of the base)
(7/8)² = 0.765625 (87.5% of the base)
(1/2)² = 1/4 (50% of the base)
(0.1)² = 0.01 (10% of the base)
Each of these results is less than the base, and with
higher positive powers, they keep getting smaller.
Answer:
The answer is 3, 6.
Step-by-step explanation:
The numbers in the top rows on the left side of the equation is 1, 4 and 2, 2.
1, 4 + 1, 2 = (1 + 2), (4 + 2) = 3, 6
Answer:
The sequence is:
10, 30, 50, 70, 90.....................
Step-by-step explanation:
We have,
First term (a) = 10
Common difference (d) = ?
Sum of first 5 terms (
) = 250
or, ![\frac{n}{2} [{2a+(n-1)d}] = 250](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B%7B2a%2B%28n-1%29d%7D%5D%20%3D%20250)
or, ![\frac{5}{2} [2*10 + 4d]=250](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20%5B2%2A10%20%2B%204d%5D%3D250)
or, ![\frac{5}{2} * 4[5+d]=250](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20%2A%204%5B5%2Bd%5D%3D250)
or, 10(5 + d) =250
or, 5 + d = 25
∴ d = 20
Now,
2nd term = a + d = 10 + 20 = 30
3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50
4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70
5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90
