If we let n represent the first number, then n + 1 is the next consecutive whole number, and n + 2 is the third number in the sequence. n + (n + 1) + (n + 2) = 3n + 3. If we solve the equation 3n + 3 = 111, we find that n = 36. Therefore, Mark is 36 years old, Taylor is 37 years old, and Brian is 38 years old.
Z = y + 1 y = x + 1 x + y + z = 111 --- put the system of linear equations into standard form --- y - z = -1 x - y = -1 x + y + z = 111 --- copy and paste the above standard form linear equations in to this solver: https://sooeet.com/math/system-of-linear-equations-solver.php --- solution: x = mark = 36 y = taylor = 37 z = brian = 38
Using the Punnette Square : R r <span>R RR Rr </span> <span>r Rr rr </span>Hence, <span>By applying the rules of probability Rr x Rr, the probability of the offspring being homozygous recessive will be one fourth or a quarter. SO the best is :
