(15y^0 x^-3 z^2/ 3x^3 y^7 z^1/2)^2

1 answer:

6 0

Hello! For this you are just going to do this step by step, and remember to use PEMDAS. That is the order in which you should do the math. The abbreviation stands for Parenthesis, exponents, multiplication, division, addition and subtraction. So lets get started!
((15y0x−3z23x3)(y7)z12)2=254x6y14z6x6=254y14z6

Hope this helps!! If you need any more help or further explanation just let me know!! :)

You might be interested in

Paloma plotted two different integers with the same absolute value on a number line. The distance between the two numbers must b

vitfil [10]

Answer:

Two integers that lie the same distance from the origin in opposite directions are called opposites. For example, "negative 5" is the opposite of "positive 5." Every number on the number line also has an absolute value, which simply means how far that number is from zero.

hope that helps

3 0

3 years ago

Read 2 more answers

Help me again sorry but it’s a emergency

ololo11 [35]

YOU CAN DO IT I BELIEVE IN YOU ❤️❤️❤️❤️

8 0

2 years ago

A real estate purveyor purchases a 60{,}00060,00060, comma, 000 square foot \left(\text{ft}^2\right)(ft 2 )(, start text, f, t,

finlep [7]

Answer:

200 feet

Step-by-step explanation:

Area of the warehouse $=60,000$ ft^2$

Let the length of the warehouse=l

The warehouse's width is exactly $\dfrac23$ of its length

Therefore: Width of the warehouse $=\dfrac23l$

Area =Length X Width

Therefore:

$\dfrac23l*l=60000\\$Cross multiply\\2l^2=60000*3\\2l^2=180000\\$Divide both sides by 2\\2l^2 \div 2=180000 \div 2\\l^2=90000\\l^2=300^2\\$Length, l=300 feet\\Recall: Width =\dfrac23l\\$Therefore, Width of the warehouse=\dfrac23*300=200$ feet$