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SpyIntel [72]
3 years ago
13

Please help someone please comment

Mathematics
1 answer:
dimaraw [331]3 years ago
6 0
#3 the answer is 4.
The reasoning for this is because x=-1 so if it is applied where x is at you have to subtract instead of multiplying in this equation. So 2xsquared is 2-1 which is 1. Same thing for 6x (6-1) which is 5. So the problem would end up being 1-5 which equals 4.
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Given that two tangent lines are constructed from the shared point A outside a circle to the points of tangency B and C, what is
Talja [164]
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Is 4.70 greater than 4.07
Aleks [24]
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4 0
3 years ago
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I still don't get it.
AlexFokin [52]
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7 0
2 years ago
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HELPPPPPPPPPPPPPPPPPPPP
SVEN [57.7K]
If x + y = 6, then solve for y to get: y = 6 - x.

Now replace y with 6 - x in both equations.

(5x)/3 + 6 - x = c

2(6 - x) = c - 4x

The upper equation is solved for c.
Now we solve the lower equation for c.

c = 2(6 - x) + 4x

c = 12 - 2x + 4x

c = 2x + 12

Since we have two equations solved for c, we substitute to get

(5x)/3 + 6 - x = 2x + 12

This is an equation in only x, so we can solve for x.

(5x)/3 - 3x = 6

5x - 9x = 18

-4x = 18

x = -9/2

Now we solve for y.

x + y = 6

-9/2 + y = 6

y = 9/2 + 12/2

y = 21/2

Now we solve for c.

c = (5x)/3 + y

c = (5 * (-9/2))/3 + 21/2

c = -45/6 + 21/2

c = -15/2 + 21/2

c = 6/2

c = 3

Answer: c = 3
7 0
3 years ago
There are 40 runners in a race. How many ways can the runners finish​ first, second, and​ third?
k0ka [10]

Answer:

117600

Step-by-step explanation:

50 x 49 x 48 = 117,600 ways

You have 50 possible for 1st, 49 for 2nd, 48 for 3rd

or

Permutations 50P3 = 117,600

5 0
3 years ago
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