n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
-----------------------------------------------------
ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
----------------------------------------------------------
n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
Answer:
In 2 hr Frank runs 8 mi farther than Ted
Step-by-step explanation:
Answer:
207
Step-by-step explanation:
1. False. 0 does not equal to 6. No answers.
2. False. x=0 means the answer is 0.
3. True.
4. False. 2 does not equal -2. No answers.
5. True.
Code: (6*6*6)-(3*3)=207
Answer:
Arav is 30 and Pawan is 40
Step-by-step explanation:
We can call Arav's age x and Pawan's age x + 10, therefore we can write the following equation:
1/7((x + 10) - 5) = 1/5(x - 5)
1/7(x + 5) = 1/5(x - 5)
5(x + 5) = 7(x - 5)
5x + 25 = 7x - 35
-2x = -60
x = 30 so x + 10 = 40