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Solve 2x+y=3 x+y=5 in substitution method

Nastasia [14]

2x+y=3
- x+y=5
---------------
x=-2

2(-2)+y=3
y=7

-2+y=5
y=7

(-2,7)

4 0

3 years ago

What is the distance between the two coordinates points c and b?

Alecsey [184]

I believe the answer is 2 if that’s an option

6 0

3 years ago

What’s the GCF of 4x^2-5x

juin [17]

The only thing you could factor out is X so it would be
X(4x-5)

5 0

3 years ago

For which value of x is ABCD a kite?

Anit [1.1K]

Answer:

83

Step-by-step explanation:

x+7+90

x=83

5 0

2 years ago

Solve this <img src="https://tex.z-dn.net/?f=4%5Cleft%285x-2%5Cright%29%3D2%5Cleft%289x%2B3%5Cright%29" id="TexFormula1" ti

vampirchik [111]

Answer:

Solution of equation ( x ) = 7

Step-by-step explanation:

In this question we have given with an equation that is 4 ( 5x - 2 ) = 2 ( 9x + 3 ). And we are asked to solve this equation that means we have to find the value of x.

Solution : -

 $\quad \longrightarrow \: 4 ( 5x - 2 ) = 2 ( 9x + 3 )$ 

Step 1 : Removing parenthesis :

$\quad \longrightarrow \:20x - 8 = 18x + 6$

Step 2 : Adding 8 from both sides :

$\quad \longrightarrow \:20x - \cancel{ 8 }+ \cancel{8} = 18x + 6 + 8$

On further calculations we get :

$\quad \longrightarrow \:20x = 18x + 14$

Step 3 : Subtracting 18 from both sides :

$\quad \longrightarrow \:20x - 18x = \cancel{18x }+ 14 - \cancel{18}$

On further calculations we get :

$\quad \longrightarrow \:2x = 14$

Step 4 : Dividing with 2 on both sides :

$\quad \longrightarrow \: \frac{ \cancel{ 2}x}{ \cancel{2}} = \cancel{\frac{14}{2} }$

On further calculations we get :

$\quad \longrightarrow \: \blue{\boxed{ \frak{x = 7}}}$

Therefore, solution of this equation is 7 or we can say that value of this equation is 7 .

Verifying : -

We are verifying our answer by substituting value of x in given equation. So ,

4 ( 5x - 2 ) = 2 ( 9x + 3 )

4 [ 5 ( 7 ) - 2 ] = 2 [ 9 ( 7 ) + 3 ]

4 ( 35 - 2 ) = 2 ( 63 + 3 )

4 ( 33 ) = 2 ( 66 )

132 = 132

L.H.S = R.H.S

Hence, Verified.

Therefore, our value for x is correct .

<h2>#Keep Learning</h2>

4 0

1 year ago

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