Answer:
5 ways
Step-by-step explanation:
We have to name the cases.
1. 4 - 0 - 0 - 0
2. 3 - 1 - 0 - 0
3. 2 - 2 - 0 - 0
4. 2 - 1 - 1 - 0
5. 1 - 1 - 1 - 1
We don't name 0 - 0 - 1 - 3 or 0 - 1 - 1 - 2 etc. because it is the same thing.
We know that the perimeter of a cylinder is 2πr we will find it as we do always. The perimeter will be :
2 pi r
= 2 pi * 20
= 40 pi
Because it says rounded to the nearest tenth the answer will be : 125.6 cm^3
Because we have a half of a cylinder we will just divide the answer we got by 2:
125.6cm^3 /2 =62.8
The answer is 62.8 cm^3
Answer:
8.95feet
Step-by-step explanation:
The set up is a right angled triangle where;
The camera's horizontal distance from the focus point = 26feet = Adjacent;
The height of the camera above the floor = Opposite = x
Angle of elevation = 19°
According to TOA in trig identity;
Tan theta = opp/adj
Tan 19 = x/26
x = 26tan 19
x = 26(0.3443)
X = 8.95feet
Hence the camera is placed at a height of 8.95feet above the floor
Answer:
29°; 61°
Step-by-step explanation:
Let one angle = x°
Other angle = (x + 32)°
x + x + 32 = 90 {given they are complementary}
2x + 32 = 90
2x = 90 -32
2x = 58
x = 58/2
x = 29
One angle = 29°
Other angle = 29 + 32 = 61°
Area of rectangle = length x breadth
= 9 x 4.25
= 38.25
= 38 sq. inches (After rounding)
Hope this helps you!
