Answer:
Explanation:
using the formula p² + 2pq + 2pr + q²+ 2qr + r² = 1 where p is IA allele is 0.35 and q is IB allele is 0.15.
Thus, the expected frequency of people with type AB blood in this population will be (2pq) = 2 x 0.35 x 0.15 = 0.105
b. The expected frequency of people with type A blood will be p² + 2pr = where r is found using the formular p + q + r = 1 = 1 - (p+q) = 1 - (0.35+0.15) = 0.5
Thus, we have the expected frequency of people with type A blood to be (0.35² + 2x0.35x0.5) = 0.4725.
c. <u> p² + 2pr</u> + <u>2pq </u>+ <u>q² + 2qr</u> +<u> r²</u>
AA AO AB BB BO OO
1850 180 635 2335
frequency of IA- p = (1850 + 180/2) / 5000 = 0.388
frequency of IB- q = (635 + 180/2) / 5000 = 0.145
frequency of i- r = 2335/ 5000 = 0.467.
since r² = 2335, r = √2335 = 48.32
using the formula p + q + r = 1
At first the cells have the same number of chromosomes as mitosis. DNA replication occurs, giving a total of 46<span> chromosomes (or </span>23<span> chromosome pairs) and </span>92 chromatids<span> (or </span>46 chromatid<span> pairs).</span>
Answer:
The termination of translation requires GTP, stop codon, and release factors.
Explanation:
hope this helps
<h3><u>Answer and explanation</u>;</h3>
- <u>According to the Law of conservation of mass; Mass cannot be created or destroyed in a chemical reaction.</u> The law of conservation of mass states that the total mass of substances taking part in a chemical reaction is conserved during the reaction. <u><em>For example in the equation;</em></u>
- <u><em>N2 + 8 H --> 2 NH3 + H2</em></u>
- <u><em>The number of hydrogen atoms and nitrogen atoms in the reactant side is equal to those on the product side.</em></u>
- Additionally; <em><u>the law of conservation of energy states that the total energy of an isolated system remains constant, that is it can not be created or destroyed, rather, it can only be transformed or transferred from one form to another.</u></em>
