That funky circle in the middle is the composition of the function. It asks you to take a function as an input and to yield an output that's another function. It's one of the five function operations, along with adding, subtracting, multiplying, and dividing.
When you compose, you might find the notation w(u(x)) easier to understand. It's saying evaluate u then evaluate w.
For our functions, the compositions are:
u(w(x)) = u(2x²) = -(2x²) - 2 = -2x² - 2
w(u(x)) = w(-x - 2) = 2(-x - 2)² = 2(x² + 4x + 4) = =2x²+ 8x +8
Now we evaluate each composition at 4.
u(w(4)) = -2(4²) - 2 = -2(16) - 2 = -32 -2 = -34
w(u(4)) = -2(2²) +8(2) + 8 = -2(4) + 16 + 8 = -8 + 16 + 8 = 16.
Thus, u(w(4)) = -34 and w(u(4)) = 16.
Answer:
2.6, 2.6081, 2.68, 3.119
Step-by-step explanation:
Look at the number before the decimal first. After look at the decimal points, the one with the smallest amount will be the least greatest (2.6) because it has no numbers after it.
Answer:
(Opt.B) 18
Step-by-step explanation:
4x = 2y - x (vertically opposite angles are equal)
4x + x = 2y
5x = 2y ----- (1)
4x + 2y + x = 180 (Linear pair angles)
5x + 2y = 180
From (1) we can understand that, the value of 5x and 2y is the same. So,
5x + 5x = 180
10x = 180
x = 180/10
x = 18
Just completing,
Putting the value of x in (1)
5*18 = 2y
90 = 2y
90/2 = y
45 = y
Hope you understand
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We will use the right Riemann sum. We can break this integral in two parts.
We take the interval and we divide it n times:
The area of the i-th rectangle in the right Riemann sum is:
For the first part of our integral we have:
For the second part we have:
We can now put it all together:
![\sum_{i=1}^{i=n} [(\Delta x)^4 i^3-6(\Delta x)^2i]\\\sum_{i=1}^{i=n}[ (\frac{3}{n})^4 i^3-6(\frac{3}{n})^2i]\\ \sum_{i=1}^{i=n}(\frac{3}{n})^2i[(\frac{3}{n})^2 i^2-6]](https://tex.z-dn.net/?f=%5Csum_%7Bi%3D1%7D%5E%7Bi%3Dn%7D%20%5B%28%5CDelta%20x%29%5E4%20i%5E3-6%28%5CDelta%20x%29%5E2i%5D%5C%5C%5Csum_%7Bi%3D1%7D%5E%7Bi%3Dn%7D%5B%20%28%5Cfrac%7B3%7D%7Bn%7D%29%5E4%20i%5E3-6%28%5Cfrac%7B3%7D%7Bn%7D%29%5E2i%5D%5C%5C%0A%5Csum_%7Bi%3D1%7D%5E%7Bi%3Dn%7D%28%5Cfrac%7B3%7D%7Bn%7D%29%5E2i%5B%28%5Cfrac%7B3%7D%7Bn%7D%29%5E2%20i%5E2-6%5D)
We can also write n-th partial sum:
Let X be the weekly incomes of a large group of executives. The weekly incomes of a large group of executives follows Normal distribution with mean $2000 and standard deviation $100.
μ =2000, σ =100
We have to find z score for income $2100 i.e x=2100
Z = 
= 
Z = 100/100
Z = 1
The z score for income $2100 is 1
