Zero if the circle is for example in the 2nd/3rd quadrant and the hyperbola is in the 1st and 4th
Answer:
1. (11r+32)+11t
2. 11(r+t)+32
3. 11r+11t+32
Step-by-step explanation:
25a-5a
Hope this helps!!!!
Answer:
ST = 20
Step-by-step explanation:
Line segment RS and segment ST must add up to line segment RT
Step 1: Define
RS = 17
ST = x + 6
RT = 3x - 5
Step 2: Set up equation
mRS + mST = mRT
17 + x + 6 = 3x - 5
Step 3: Solve for <em>x</em>
x + 23 = 3x - 5
23 = 2x - 5
28 = 2x
x = 14
Step 3: Find mST
ST = x + 6
ST = 14 + 6
ST = 20
128 miles
You can get this by setting up a proportion.
.75/8 = 12/x
Then cross multiply
12*8 = .75 x
96 = .75x
128 = x
