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muminat
3 years ago
13

The centralized computer technology department of Hardy Company has expenses of $78,400. The department has provided a total of

11,200 hours of service for the period. The Retail Division has used 9,856 hours of computer technology service during the period, and the Commercial Division has used 1,344 hours of computer technology service. How much should each division be charged for computer technology department services
How much should each division be charged for computer technology department services?
Business
1 answer:
Artemon [7]3 years ago
6 0

Answer:

Expenses to be apportioned to Retail Division $68,992

Expenses apportion to Commercial Division

$9,408

Total Expenses $ 78,400

Explanation:

Hardy Company Computer Technology Dept. expenses to be apportioned to Retail Division and Commercial Division.

Total Expenses $ 78,400

Hours used by Retail Division 9,856

Hours used by Commercial Division 1,344

Total hours put in by Computer Tech Dept. 11,200 Hours

Therefore, expenses to be apportioned to Retail Division

= 9,856/11,200 X $ 78,400

= $68,992

Expenses apportion to Commercial Division

= 1,344/11,200 X $78,400 = $9,408

Total Expenses $ 78,400

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inessss [21]

Answer:

Instructions are below.

Explanation:

Giving the following information:

Sales:

January 130,000

February 160,000

March 200,000

April 215,000

May 180,000

June 240,000

Beginning inventory for 2014 is 30,000 units.

The budgeted inventory at the end of a month is 40 percent of units to be sold the following month.

The purchase price per unit is $5.

<u>To calculate the production required for each month, we need to use the following formula:</u>

Production= sales + desired ending inventory - beginning inventory

<u>January:</u>

Sales= 160,000

Desired ending inventory= (160,000*0.4)= 64,000

Beginning inventory= (30,000)

Total= 164,000

Total cost= 164,000*5= $820,000

F<u>ebruary:</u>

Sales= 130,000

Desired ending inventory= (200,000*0.4)= 80,000

Beginning inventory= (64,000)

Total= 146,000

Total cost= 146,000*5= $730,000

<u>March:</u>

Sales= 200,000

Desired ending inventory= (215,000*0.4)= 86,000

Beginning inventory= (80,000)

Total= 206,000

Total cost= 206,000*5= $1,030,000

<u>April:</u>

Sales= 215,000

Desired ending inventory= (180,000*0.4)= 72,000

Beginning inventory= (86,000)

Total= 201,000

Total cost= 201,000*5= $1,005,000

<u>May:</u>

Sales= 180,000

Desired ending inventory= (240,000*0.4)= 96,000

Beginning inventory= (72,000)

Total= 204,000

Total cost= 204,000*5= $1,020,000

3 0
4 years ago
How would producers respond if the figure for changes in stocks were postive ?​
Rama09 [41]

Answer:

this is not the answer

Explanation:

Consumers and producers react differently to price changes. ... Both of these changes are called movements along the demand or supply

5 0
3 years ago
On May 3, 2020, Concord Company consigned 80 freezers, costing $540 each, to Remmers Company. The cost of shipping the freezers
NeX [460]

Answer:

a) $22,010

b) $3,780

c) $25,790

Explanation:

a) In calculating the value of inventory still left, the total value needs to be calculated first,

= (80 freezers * $540) + $820 ( transport fees)

= 43,200 + 820

= $44,020

40 out of 80 freezers have not been sold so,

= 40/80 * 44,020

= $22,010

b) In calculating the profit, subtract the expenses from the sales

Sales = 40 * 700

= $28,000

= 28,000 - Cost of refrigerators - commission of 6% of sales - advertising - installation

= 28,000 - 22,010 - (28,000*0.06) - 180 - 350

= $3,780

c) The amount remitted by the consignor will be,

= Sales - commission - advertising - installation

= 28,000 - (28,000 * 0.06) - 180 - 350

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7 0
3 years ago
Consider this problem: Fast Auto Service provides oil and lube service for cars. It is known that the mean time taken for oil an
astraxan [27]

Answer:

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Explanation:

From the given problem data, we have:

Let Y be the random variable which follows the normal distribution.

So,

Y ~ N(u = 15, SD = 2.4

Where, u = mean and SD = Standard Deviation

Let the maximum time guaranteed is = M

So,

P (Y > M) = 0.05   equation 1

Convert this equation 1 into standard normal variable, that is,

P(Y> M) = 0.05

1 -  P(Y \leq M) = 0.05

P(Y \leq M) = 1 - 0.05

P(Y \leq M) = 0.95

P(\frac{Y-u}{SD} \leq \frac{M-u}{SD} ) = 0.95

P ( Z \leq \frac{M - 15}{2.4} )  = 0.95     Equation 2

From the equation 2, we have,

\frac{M-15}{2.4} = 1.644853627  

1.644853627 value is from using the function of Excel

( =NORSINV(0.95)) = 1.644853627

So,

M = 1.644853627 + 2.4 + 15

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Hence, the maximum time guaranteed = 19.04 minutes.

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3 years ago
A company had net cash flows from operations of $120,000, total cash flows of $500,000, and average total assets of $2,500,000.
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Answer:

cash flow on total assets ratio = 4.8 %

so correct option is a) 4.8%

Explanation:

given data

net cash flows = $120,000

total cash flows = $500,000

average total assets = $2,500,000

to find out

cash flow on total assets ratio

solution

we get here cash flow on total assets ratio that is equal to

cash flow on total assets ratio = Operating cash flow ÷ Average total assets   ..................1

put here value we get

cash flow on total assets ratio = \frac{120000}{2500000}

cash flow on total assets ratio = 4.8 %

so correct option is a) 4.8%

3 0
4 years ago
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