1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
docker41 [41]
2 years ago
15

Each vertical cross-section of the triangular

Mathematics
2 answers:
Blizzard [7]2 years ago
3 0

Answer:

The vertical height is h=3\ units

Step-by-step explanation:

we know that

In the right triangle ABC

see the attached figure

To find the height h apply the Pythagoras Theorem

c^{2}=a^{2}+b^{2}

we have

c=AB=3\sqrt{2}\ units

a=BC=6/2=3\ units

b=AC=h\ units

substitute

(3\sqrt{2})^{2}=3^{2}+h^{2}

18=9+h^{2}

h^{2}=18-9=9

h=3\ units

Ostrovityanka [42]2 years ago
3 0

Answer:3

Step-by-step explanation:

You might be interested in
What sums are equal to 6/12?
nadya68 [22]

Hey there!

"What sums are equal to \bold{\frac{6}{12}}?"

\bold{\frac{6}{12}=\frac{1}{2}=0.5 }

  • It <em><u>can't</u></em> be \bold{A. \frac{6}{12} + \frac{6}{12}+ \frac{6}{12}+\frac{6}{12}+\frac{6}{12}+\frac{6}{12}}   because the answer would be \bold{3}
  • It <u><em>can </em></u> be \bold{B.\frac{2}{12} + \frac{1}{12} + \frac{1}{12} +\frac{2}{12}}
  • It <u><em>can</em></u> also be \bold{C. \frac{5}{12} + \frac{1}{12}}
  • It <em>can</em> also again be \bold{\frac{1}{12}+\frac{1}{12}+\frac{1}{12}+\frac{3}{12}}
  • \boxed{\boxed{\bold{Answers: B,C,D}}}}

Good luck on your assignment and enjoy your day!

~\bold{LoveYourselfFirst:)}



6 0
2 years ago
Read 2 more answers
A rectangle is 2.8 in wide and 3.9 in tall. If it is enlarged to a width of 22.4 in, then how tall will it be?
Greeley [361]

Answer:A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
5. f(x) = 3x³ - 4x² +6x and g(x)=5x ³+ 2x²- 3x. What is f(x) - g(x)?
sasho [114]

Answer:

<h2>A. -2x³ - 6x² + 9x</h2>

Step-by-step explanation:

f(x)=3x^3-4x^2+6x\\\\g(x)=5x^3+2x^2-3x\\\\f(x)-g(x)=(3x^3-4x^2+6x)-(5x^3+2x^2-3x)\\\\=3x^3-4x^2+6x-5x^3-2x^2-(-3x)\qquad\text{combine like terms}\\\\=(3x^3-5x^3)+(-4x^2-2x^2)+(6x+3x)\\\\=-2x^3-6x^2+9x

8 0
3 years ago
I'm confused, please help. :/
vampirchik [111]

uh i did this wrong so uh just ignore what i said

5 0
3 years ago
Read 2 more answers
A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s.
Harman [31]
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:
0=-16 t^{2} +122t+99
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
-99=-16 t^{2} +122t+99
-16 t^{2} +122+198=0

Now we can apply the quadratic formula t= \frac{-b+or- \sqrt{ b^{2} -4ac} }{2a} where a=-16, b=122, and c=198
t= \frac{-122+or- \sqrt{ 122^{2}-(4)(-16)(198) } }{(2)(-16)}
t= \frac{-122+ \sqrt{27556} }{-32} or t= \frac{-122- \sqrt{27556} }{-32}
t= \frac{-122+166}{-32} or t= \frac{-122-166}{-32}
t= \frac{-11}{8} or t=9

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
5 0
3 years ago
Read 2 more answers
Other questions:
  • The vertex of the graph of y=(x-1)^2-5 is
    10·2 answers
  • 11
    12·1 answer
  • The volume of a cube is found using the formula l3, where l is the side length. What is the volume of a cube, in cubic feet that
    6·1 answer
  • Solve each system of equations by substitution <br> X + 3y = 6<br> -x + y = -7
    5·1 answer
  • PLEASE ANSWER FOR BRAINLIST!!!!!!!!
    8·1 answer
  • Work out<br> a the length of arc AB<br> b the area of the shaded sector.
    12·2 answers
  • Henlo :D <br><br> I need a friend :3
    11·2 answers
  • I got the answer which is A and pls tell me if im right
    5·2 answers
  • Pls help really confusing
    12·1 answer
  • You start at (0, 0). You move up 3 units. Where do you end?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!