Question

Each vertical cross-section of the triangular

Answer 1

Answer:

The vertical height is $h=3\ units$

Step-by-step explanation:

we know that

In the right triangle ABC

see the attached figure

To find the height h apply the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

we have

$c=AB=3\sqrt{2}\ units$

$a=BC=6/2=3\ units$

$b=AC=h\ units$

substitute

$(3\sqrt{2})^{2}=3^{2}+h^{2}$

$18=9+h^{2}$

$h^{2}=18-9=9$

$h=3\ units$

Answer 2

Answer:3

Step-by-step explanation: