The proof is given below. Please go through it.
Step-by-step explanation:
To solve Δ ABC ≅ Δ DBC
From Δ ABC and Δ DBC
AB = BD (given)
AC = CD (given)
BC is common side
By SSS condition Δ ABC ≅ Δ DBC ( proved)
To solve Δ EHF ≅ Δ GHF
Δ EHF and Δ GHF
EH = HG ( given)
∠ EFH = ∠ GFH ( each angle is 90°)
HF is common side
By RHS condition
Δ EHF ≅ Δ GHF
Answer:
D.............................................
Step-by-step explanation:
im sorry if im wrong
4 6/9= 38/9
7 5/3= 26/3
3 7/8= 31/8
5 19/14 =89/14
Answer:
Explanation:
The question states the <em>congruent</em> images:
- ABCD ≅ FGHI ≅ JKLM ≅ NOPQ ≅ RSTU
The order of the letters matters.
For instance, ABCD ≅ FGHI means that the vertex A is transformed into vertex F, the vertex B is transformed into the vertex G, the vertex C is transformed into vertex H, and the vertex D is transformed into vertex I.
From the images, the square ABCD is just shifted 9 units down to form the square FGHI. No refelection is needed.
As per the square RSTU only a reflection of square ABCE accross the y-axis makes the vertex A into vertex R, the vertex B into the vertex S, the vertex C into the vertex T, and the vertex D into the vertex U.
Answer:
The answer would be B
Step-by-step explanation:
All you have to do is multiply to see what its multiplied by to get the sizes of T Which is all by 4 so your answer is B
