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Karo-lina-s [1.5K]
3 years ago
6

Form the intersection for the following sets.

Mathematics
1 answer:
Luden [163]3 years ago
6 0

Answer:

Your required answer is option is {20}.

Step-by-step explanation:

Hey, there!!

The reason for above answer is we generally find intersections among the sets by extracting the common elements of the sets.

Here,

R = {10,15,20}

S = {20,25}.

Now, 20 is common im both so,

R intersection S = {20}.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Multiplication by 10ⁿ → move decimal n places to the right.

Multiplication by 10⁻ⁿ → move decimal n places to the left.

For n ∈ N

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Is -5/12 and irrational or rational
oksian1 [2.3K]

Answer:

Rational.

Step-by-step explanation:

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This is the answer 2.5
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Eight sided dice can be described as two square based pyramids stuck together at
kobusy [5.1K]
It costs $3.63 more for the gold die than the gold plated die.

The volume of each half of the die is given by the formula

V=1/3s³.

This means the total volume is V = 2(1/3s³) = 2(1/3(2³)) = 16/3 = 5.33 mm³.

For the solid gold die, we know that it weighs 0.02g per mm³:

5.33(0.02) = 0.1066g

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For the plastic die, plastic weighs 0.01 g per mm³:
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Plastic costs $10 per gram:
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We also need to find the surface area, as it will be painted.  Each face is an equilateral triangle; the area of a triangle is given by the formula

A = 1/2bh

We need to use the Pythagorean theorem to find the height.  The height will be one leg and 1/2 of the base will be the other; the slanted side will be the hypotenuse:

h² + (1/2(2))² = 2²
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The area of the triangle would then be A = 1/2bh = 1/2(2)(√3) = √3.  There are 8 such faces on the die, so the total surface area would be 8√3 = 13.86mm².

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Together the cost for the plastic is 0.14+0.53 = $0.67.

The difference between it and the cost for the gold die is 4.30 - 0.67 = $3.63.
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Help me out please! Any unrelated answers will be reported, so don't try :)
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Try doing A, 2/3 Hopefully it helps you, I'm not good with fractions.

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