Question

A baseball team played 32 games and lost 8 Katy was the catcher in 5/8 of the winning games and 1/4 of the losing games

Answer 1

Answer:

a. Fraction of games won by team is $\frac{3}{4}$.

b. Total games played by Katy as catcher is 17.

Step-by-step explanation:

Here is the complete question: A baseball team played 32 games and lost 8 Katy was the catcher in 5/8 of the winning games and 1/4 of the losing games.

a. What fraction of the games did the team win?

b. In how many games did Katy play catcher?

Given: Total number of games= 32

           Total games lost= 8.

           Katy was the catcher in 5/8 of the winning games.

           Katy was the catcher in 1/4 of the losing games.

Now, finding total number games that team won.

Winning total= $32-8= 24$

∴ Total number of games that team won is 24.

Next finding fraction of the games did the team win.

Fraction of games won by team is $\frac{Games\ won}{Total\ number\ of\ games}$

∴ Fraction of games won by team = $\frac{24}{32} = \frac{3}{4}$

Fraction of games won by team is $\frac{3}{4}$

Lets find out numbers of games Katy play chatcher.

We know, Katy was the catcher in 5/8 of the winning games.

∴ Katy was catcher= $\frac{5}{8} \times 24= 5\times 3$

Katy was catcher in 15 of the wining games.

We also know, Katy was the catcher in 1/4 of the losing games.

∴ Katy was catcher= $\frac{1}{4} \times 8= 1\times 2$

Katy was the catcher in 2 of the losing games.

Total games played by Katy as catcher= Catcher in wining games+ catcher in losing games.

∴ Total games played by Katy as catcher= $15+2= 17 games.$

Hence, total games played by Katy as catcher is 17.