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Anna71 [15]
3 years ago
14

6 = r + 2 Addition and Subtraction Equations 11.2

Mathematics
1 answer:
Taya2010 [7]3 years ago
3 0

Answer:

I'm not sure what you are looking for but I'm assuming you are finding r.

r is equal to 4.

Step-by-step explanation:

6 = r + 2

In order to find r, you have to subtract 2 from 6.

So, r = 6 - 2 = 4

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A four-person committee is chosen from a grous of eight boys and six girls.
Leviafan [203]

The probability that it consists of all boys is 8/14. You're Welcome!

Step-by-step explanation:

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How does using a model help me multiply decimals by whole numbers?
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Counting them it simple
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Question 9 of 15 (1 point)
mote1985 [20]

The number is -9

Step-by-step explanation:

Let x be the number then according to given statement

4x+10 = x-17

Subtracting 10 from both sides

4x+10-10 = x-17-10\\4x = x-27

Subtracting x from both sides

4x-x = x-x-27\\3x = -27

Dividing both sides by 3

\frac{3x}{3} = \frac{-27}{3}\\ x = -9

<u>Verification:</u>

4(-9)+10 = -9-17\\-36+10=-26\\-26=-26

The number is -9

Keywords: Linear equation, variables

Learn more about linear equation at:

  • brainly.com/question/4767370
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#learnwithBrainly

7 0
3 years ago
Just need the equation
Anna007 [38]

a. $ x = -2\\b. $ x = \frac{3}{2} \\c. $ x = 0\\d. $ x = -\frac{1}{5}

Each of the equations can be solved as shown below:

a. 3x + 7 = - x - 1

3x + 7 + x  = - x - 1 + x (<em>addition property of equality</em>)

4x + 7  = - 1\\4x + 7 - 7 = -1-7 (<em>Subtraction property of equality</em>)

4x = -8\\\frac{4x}{4} = \frac{-8}{4}<em> (Division property of equality)</em>

<em />x = -2

b. 1 - 2x + 5 = 4x - 3\\

<em>Add like terms </em>

<em />6 - 2x = 4x - 3\\\\6 - 2x - 6 = 4x - 3 - 6 (<em>Subtraction property of equality</em>)

- 2x = 4x - 9\\-2x - 4x = 4x -9 - 4x<em> (Subtraction property of equality)</em>

<em />-6x = -9 \\\frac{-6x}{-6} = \frac{-9}{-6}<em> (Division property of equality)</em>

<em />x = \frac{3}{2}

c. 4x - 2 + x =-2 + 2x\\

5x - 2 = -2 + 2x\\5x - 2x = -2 + 2\\3x = 0\\ x = \frac{0}{3} \\x = 0

d. 3x - 4 + 1 = - 2x -5 + 5x\\

3x - 3 = - 7x -5\\3x + 7x = 3 - 5\\10x = -2\\x = \frac{-2}{10} \\x = -\frac{1}{5}

<em>The value of x in each </em><em>equation</em><em> are:</em>

<em />a. $ x = -2\\b. $ x = \frac{3}{2} \\c. $ x = 0\\d. $ x = -\frac{1}{5}

Learn more here:

brainly.com/question/1527981

5 0
3 years ago
A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec
zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0
3 years ago
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