We use the concept on colligative properties to calculate the number of moles in the system above. We calculate as follows:
ΔT = -kf(m)
where ΔT is the change in freezing point, kf is the freezing point depression and m is the molality of the solution.
-10 = -1.86(m)
m = 5.37 mol/kg
number of moles = 5.37 (4.50) = 24.19 moles of methanol
Answer:
carboxyl group (COOH) and amines
Explanation:
Answer:
Option-1 (Solubility and Molecular polarity) is the correct answer.
Explanation:
Thin Layer Chromatography is employed to separate a mixture of non volatile compounds. In this technique an adsorbent material like silica gel is coated on a plastic, glass or aluminium sheet. Then the mixture of compounds is applied at the bottom of sheet and the sheet is placed in the container containing a solvent system. It is observed that the solvent starts travelling upward through capillary action.
While the solvent is running the mixture of compounds starts separating from each other. This separation is due to following physical properties.
1) Solubility of Mixture in Solvent:
In a mixture those compounds which has more solubility in solvent will travel more and will give greater Rf value and the less soluble will left behind with smaller Rf value. Hence due to solubility a mixture of compounds can be separated.
2) Polarity of Molecules:
As the stationary phase (adsorbent material) is polar in nature, so in mixture those compounds which are less polar will less interact with the stationary phase and will travel more with greater Rf value, while, more polar molecules will form stronger interactions with the stationary phase, hence will travel less and therefore, will show smaller Rf values.
Explanation:
(6.1). The reaction equation will be as follows.
Assuming the value of 
as 
and let the solubility of each specie involved in this reaction is "s". The expression for will be as follows.
![K_{sp} = [Ba^{2+}][SO^{-}_{2}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BBa%5E%7B2%2B%7D%5D%5BSO%5E%7B-%7D_%7B2%7D%5D)
(Solids are nor considered)
= 
s = 
= 
= 
Therefore, solubility of barium sulfate in water is .
(6.2). As the molar mass of 
is 233.38 g/mol
Therefore, the solubility is g/L will be calculated as follows.
= 
Therefore, solubility of barium sulfate in grams per liter is .
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