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4 years ago

Which of the following statements is NOT true about saturated fats?

Chemistry

1 answer:

ch4aika [34]4 years ago

8 0

Answer:

A. They contain many carbon-carbon double bonds.

Explanation:

Saturated fats do not contain double bonds between the carbons. The carbons attached only by single bonds all saturated with hydrogen atoms or in other words, they have many hydrogen atoms clinging to the main skeletal carbon chain, and thus the word saturated.

Saturated fats are the type of fats that are not healthy.

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The complete combustion of acetic acid, HC2H3O2(I) to form water, H2O(I), and CO2(g), at constant pressure releases 871.7 kJ of

lbvjy [14]

Answer:

HC2H3O2(I) + O2(g) ---> H2O(I) + CO2(g) ΔH= -72.35 kJ

Explanation:

We know that 5.0 g of acetic acid will contain, 5.0g/60 g/mol = 0.083 moles of acetic acid

Now from the reaction equation;

1 mole of acetic acid evolved -871.7 KJ of heat

0.083 moles of acetic acid will evolve 0.083 * -871.7 = -72.35 KJ

For 5.0 g of acetic acid, we can write;

HC2H3O2(I) + O2(g) ---> H2O(I) + CO2(g) ΔH= -72.35 kJ

3 0

3 years ago

What is the entropy change for freezing 2.71 g of C2H5OH at 158.7 K? ∆H = −4600 J/mol. Answer in units of J/K.

Ira Lisetskai [31]

Answer:

-1.71 J/K

Explanation:

To solve this problem we use the formula

ΔS = n*ΔH/T

Where n is mol, ΔH is enthalpy and T is temperature.

ΔH and T are already given by the problem, so now we calculate n:

Molar Mass C₂H₅OH = 46 g/mol

2.71 g C₂H₅OH ÷ 46g/mol = 0.0589 mol

Now we calculate ΔS:

ΔS = 0.0589 mol * −4600 J/mol / 158.7 K

ΔS = -1.71 J/K

4 0

3 years ago

A mixture of N2, O2, and Ar has mole fractions of 0.25, 0.65, and 0.10, respectively. What is the pressure of N2 if the total pr

s344n2d4d5 [400]

Answer:

Partial pressure of nitrogen gas is 0.98 bar.

Explanation:

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gases.

$P=p_{N_2}+p_{O_2}+p_{Ar}$

$p_{N_2}=P\times \chi_{N_2}$

$p_{O_2}=P\times \chi_{O_2}$

$p_{Ar}=P\times \chi_{Ar}$

where,

$P$ = total pressure = 3.9 bar

$p_{N_2}$ = partial pressure of nitrogen gas

$p_{O_2}$ = partial pressure of oxygen gas

$p_{Ar}$ = partial pressure of argon gases

$\chi_{N_2}$ = Mole fraction of nitrogen gas = 0.25

$\chi_{O_2}$ = Mole fraction of oxygen gas = 0.65

$\chi_{Ar}$ = Mole fraction of argon gases = 0.10

Partial pressure of nitrogen gas :

$p_{N_2}=P\times \chi_{N_2}=3.9 bar\times 0.25 =0.98 bar$

Partial pressure of oxygen gas :

$p_{N_2}=P\times \chi_{O_2}=3.9 bar\times 0.65=2.54 bar$

Partial pressure of argon gas :

$p_{N_2}=P\times \chi_{Ar}=3.9 bar\times 0.10=0.39 bar$

7 0

4 years ago

HNO3 is an Arrhenius acid and increases the concentration of what??? when added to water.

sineoko [7]

When nitric acid is added to water, the concentration of hydronium ions would increase since the nitric acid dissociates into ions, the hydronium ions and the nitrate ions. Hope this answers the question. Have a nice day. Feel free to ask more questions.

3 0

4 years ago

A centimeter and millimeter differ from each other by a factor of _____ ?

Liono4ka [1.6K]

The answer is: "10" .
_______________________________________________________________
" A centimeter and millimeter differ from each other by a factor of "10" .
_______________________________________________________________
Note:
____________________________
100 cm = 1 m

1000 mm = 1m

____________
100 * (10) = 1000 .
_________________
The answer is: "10".
__________________________________________________________
" A centimeter and millimeter differ from each other by a factor of "10".
__________________________________________________________

7 0

3 years ago