Answer:
C) 10
Step-by-step explanation:
The triangle on the right shows that the side AB is 4 and the triangle on the left shows that the side DE is 8. Based on these two numbers I can conclude that the triangle DEF is double the size of triangle ABC. With this information, I can find e by doing 5*2=e and get 10 as my answer.
Hope this helps you :)
The correct answer for this question is this one:
As shown in the graph, The curved part of this figures is a semicircle.
What is the area of this figure?
28+8.125π units²
<u>28+16.25π units²</u>
14+8.125π units²
14+16.25π units²
Hope this helps answer your question and have a nice day ahead.
<h3>The value of x is 4.10</h3>
<em><u>Solution:</u></em>
Given that,
The angle Johnny holds his pen on paper creates a linear pair
Angles in a linear pair are supplementary angles
Two angles are supplementary, when they add up to 180 degrees
The measure of one angle is 13x + 7
The measure of the second angle is one less than twice the first angle
Therefore,
Measure of second angle = twice the first angle - 1
Measure of second angle = 2(13x + 7) - 1
Measure of second angle = 26x + 14 - 1
Measure of second angle = 26x + 13
Therefore,
Measure of first angle + measure of second angle = 180
13x + 7 + 26x + 13 = 180
39x + 20 = 180
39x = 180 - 20
39x = 160
x = 4.1
Thus value of x is 4.10
Answer:
a. 1620-x^2
b. x=810
c. Maximum value revenue=$656,100
Step-by-step explanation:
(a) Total revenue from sale of x thousand candy bars
P(x)=162 - x/10
Price of a candy bar=p(x)/100 in dollars
1000 candy bars will be sold for
=1000×p(x)/100
=10*p(x)
x thousand candy bars will be
Revenue=price × quantity
=10p(x)*x
=10(162-x/10) * x
=10( 1620-x/10) * x
=1620-x * x
=1620x-x^2
R(x)=1620x-x^2
(b) Value of x that leads to maximum revenue
R(x)=1620x-x^2
R'(x)=1620-2x
If R'(x)=0
Then,
1620-2x=0
1620=2x
Divide both sides by 2
810=x
x=810
(C) find the maximum revenue
R(x)=1620x-x^2
R(810)=1620x-x^2
=1620(810)-810^2
=1,312,200-656,100
=$656,100
Answer:
Step-by-step explanation:
Distance covered by the train in crossing the pole = 100 m.
- Hence, the speed of the train is 72 km/h
