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Ghella [55]
3 years ago
11

Which values are solutions to the inequality x^2<81

Mathematics
1 answer:
Aloiza [94]3 years ago
7 0

Isolate the x. Root both sides

√x²< √81

x < 9 is your answer

hope this helps

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Which graph represents the solution for the equation 1/6x=-2x+5
Varvara68 [4.7K]
More information please.
8 0
3 years ago
Two bags contain coloured cubes.
spayn [35]

Answer:

equal

Step-by-step explanation:

Bag 1 has 3 red cubes and 1 blue cube.  = 4 cubes

Bag 2 has 3 green cubes, 1 yellow cube, and 1 red cube.= 5 cubes

P ( red bag 1) = red /total = 3/4

P (yellow  bag 2) = yellow /total = 1/5

P(red bag1 , yellow bag2) = 3/4* 1/5 = 3/20

P ( blue bag 1) =blue /total =1/4

P (green  bag 2) = green /total = 3/5

P(blue bag1 , green bag2) = 1/4* 3/5 = 3/20

The probabilities are equal

8 0
3 years ago
I need help. You can have brainliest. Plz <br> Thanks
Katena32 [7]

Answer:

B:

Step-by-step explanation:

3 0
2 years ago
Please help me with this question!
gavmur [86]
First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway   thus

\bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentrated\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{first sol'n}&11&x&11x\\&#10;\textit{second sol'n}&4&0.55&2.20\\&#10;------&-----&-------&-------\\&#10;mixture&y&0.77&0.77y&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;11+4=y\implies 15=\boxed{y}\\&#10;11x+2.2=0.77y\\&#10;----------\\&#10;11x+2.2=0.77\cdot \boxed{15}&#10;\end{cases}

solve for "x"
6 0
3 years ago
Will mark brainliest and give 20 points! In what ways can vertical, horizontal, and oblique asymptotes be identified? Please use
spayn [35]
If both polynomials are the same degree, divide the coefficients of the highest degree terms. If the polynomial in the numerator is a lower degree than the denominator, the x-axis (y = 0) is the horizontal asymptote<span>.</span>The curves approach these asymptotes but never cross them. To find the vertical asymptote(s) of a rational function, simply set the denominator equal to 0 and solve for x.Finding Slant Asymptotes<span> of Rational Functions.

A </span>slant (oblique) asymptote occurs<span> when the polynomial in the numerator is a higher degree than the polynomial in the denominator. To </span>find the slant asymptote<span> you must divide the numerator by the denominator using either long division or synthetic division.
</span>
3 0
3 years ago
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