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Karolina [17]
3 years ago
8

waco, tx, has an elevation of 405 feet. dallas, tx, has an elevation of 463feet . about how many feet greater is dallas elevatio

n than wacos elevation?
Mathematics
2 answers:
ollegr [7]3 years ago
5 0
Dallas is 58 feet high in elevation than Waco is.
rodikova [14]3 years ago
4 0

Answer:  Dallas elevation is 58 feet greater than Wacos elevation.

Step-by-step explanation:

Given : Waco, tx, has an elevation of 405 feet.

Dallas, tx, has an elevation of 463 feet .

∵ 405 feet < 463 feet

So, It is clear that the Dallas, tx, has higher elevation as compare to Waco, tx.

Difference in elevation : 463 feet - 405 feet

=58 feet

Hence,  Dallas elevation is 58 feet greater than Wacos elevation.

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andre [41]

Answer:

Step-by-step explanation:

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8 0
3 years ago
Fas
Mrrafil [7]

The graph is vertically stretched by a factor of 2 and translated 3 units right when it is transformed. Option A is correct.

<h3>What is transformation of a function?</h3>

Transformation of a function is shifting the function from its original place in the graph.

Types of transformation-

  • Horizontal shift- Let the parent function is f(x). Thus by replacing parent function with f(x-b) shifts the graph b units right and by replacing parent function with f(x+b) shifts the graph b units left.
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The given function is,

f(x) = x^3

This function is changed to the function,

g(x) = 2f(x -3),

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Thus, the graph is vertically stretched by a factor of 2 and translated 3 units right when it is transformed. Option A is correct.

Learn more about the transformation of a function here;

brainly.com/question/10904859

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5 0
2 years ago
A- CE=CD <br> B- CE = CA <br> C- BF=DF <br> D- DF=EF<br><br> please help!!
Oksana_A [137]

The perpendicular bisector theorem gives the statements that ensures

that \overleftrightarrow{FG} and \overleftrightarrow{AB} are perpendicular.

The two statements if true that guarantee  \overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB} are;

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Reasons:

The given diagram is the construction of the line \mathbf{\overleftrightarrow{FG}} perpendicular to line \mathbf{\overleftrightarrow{AB}}.

Required:

The two statements that guarantee that  \overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB}.

Solution:

From the point <em>C</em> arcs <em>E</em> and <em>D</em> are drawn to cross line \overleftrightarrow{AB}, therefore;

\overline{CE} = \mathbf{\overline{CD}} arcs drawn from the same radius.

\overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB}, given.

Therefore;

\overline{DF} = \overline{EF}  by perpendicular bisector theorem.

Learn more about the perpendicular bisector theorem here:

brainly.com/question/11357763

7 0
3 years ago
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True [87]

Answer:

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And the point of interesection for the system of equations in the problem you attached as an image is (2,-1)

I attached a photo below, and one of how to graph it

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Nana76 [90]
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