Answer:
See the explanation
Explanation:
Answer 1.
As given that in F1 all are short and white then it can be said according to Mendel's law that short and white are dominant over tall and purple.
Let S for short s for tall and W for white and w for purple allele.
So the genotype of short purple will be Ssww or SSww. So In first case Ssww self crossed then resultant offsprings will be,
................ Sw .................... sw
Sw ........ SSww ............. Ssww
sw ........ Ssww .............. ssww (tall and purple)
So from this 1/4 will be tall and purple while 3/4 will be short and purple.
In second case SSww only short purple progeny will appear.
Answer 2.
2. a) The female progeny will not show any trait because there are two X chromosome in females , so female offspring can be carrier but not show any trait in case of X- linked trait.
2. b) Half of male offsprings show trait because X is inherited from mother. So the chance of having X-linked recessive allele is 1/2.
2. c) The chance of having X linked affect allele in daughter is 1/2. So the chance of inheriting that X to son will be 1/2 so in total there is chance of 1/4 that son will be affected.
2. d) the chance of first child show this trait will be 1/4 in case of male offspring while 0 in case of female offspring.
Hope this helps!
<h2>Answer:</h2>
The offspring population will contains the desirable characteristics of both fantail pigeon and the fantail pigeon.
<h3>Explanation:</h3>
- The selective breeding is the planned breeding between two organism of the population with desirable properties to result in the new traits from both parents in the single next generation offspring.
- In this case, the offspring of the pouter pigeon and the fantail pigeon will contain the traits of pouter and it also has fantail.
- The new generation will be selective breed an it is from the breeding of intra specie organism. If breeding is inter specie than the offspring is most probably infertile.
<em>the correct option for this is B>></em>
The plant goes into shock
