The answer is -3x^2+10xy+8y^2
Which is it
2x times y times 3 = 6xy
or,
2xxyx3= 6x^3y
<u>9x</u> = <u>3y + 5</u>
9 9
x = 1/3y + 5/9
x - 5/9 = 1/3y + 5/9 - 5/9
x - 5/9 = 1/3y
3(x - 5/9) = 1/3y · 3
3x - 1 2/3 = y
y = 3x - 1 2/3
Answer:
RP: x equals 0
JH: x equals -11
EG: x equals 9
First we find the common difference...to do this we subtract the first term from the second term. -7 - (-1) = -7 + 1 = -6
now we are going to find the 10th term
an = a1 + (n-1)*d <== formula for finding any term in arithmetic series
a1 = 1st term, d = common difference, n = term we want to find
now we sub
a10 = -1 + (10 -1) * -6
a10 = -1 + (9 * -6)
a10 = -1 - 54
a10 = - 55
now we will find the sum
Sn = (n (a1+ an)) / 2 <== formula for finding the sum
S10 = (10(-1 - 55))/2
S10 = (10(-56) / 2
S10 = -560/2
S10 = - 280
so the sum of the first 10 numbers is -280
