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3 years ago

5

Which graph shows rotation?

2 answers:

frozen [14]3 years ago

6 0

Answer:

B

Step-by-step explanation:

Rufina [12.5K]3 years ago

5 0

C is the answer. A and D are reflections and b is a translation

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F(x)=2x-3 g(x)=x^2+1 find g(2)

Hitman42 [59]

Answer:

$g(2)=5$

Step-by-step explanation:

since g(x) is equal to $x^2+1$ , you just plug in the value of 2 for x, to get $2^2+1$ , and 2 to the power of 2 (also known as 2 squared) is equal to 4, which makes your equation $4+1$ , which equals 5.

3 0

2 years ago

a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l

GrogVix [38]

Answer:

$\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}$

Step-by-step explanation:

The equation of a line:

$y=mx+b$

We have

$m=\dfrac{2}{3}$

substitute:

$y=\dfrac{2}{3}x+b$

The formula of a distance between a point and a line:

General form of a line:

$Ax+By+C=0$

Point:

$(x_0,\ y_0)$

Distance:

$d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}$

Convert the equation:

$y=\dfrac{2}{3}x+b$ |<em>subtract $y$ from both sides</em>

$\dfrac{2}{3}x-y+b=0$ |<em>multiply both sides by 3</em>

$2x-3y+3b=0\to A=2,\ B=-3,\ C=3b$

Coordinates of the point:

$(0,\ 0)\to x_0=0,\ y_0=0$

substitute:

$d=4$

$4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}$

$4=\dfrac{|3b|}{\sqrt{13}}\qquad|$ |<em>multiply both sides by $\sqrt{13}$ </em>

$4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}$ |<em>divide both sides by 3</em>

$b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}$

Finally:

$y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}$

4 0

2 years ago

The function ƒ(x) = −(x + 3)^2 − 4 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an

Nookie1986 [14]

Answer:

Step-by-step explanation:

The second one I believe.

3 0

2 years ago

(1 point) Find an equation of the largest sphere with center (5,3,5)(5,3,5) and is contained in the first octant. Be sure that y

Hoochie [10]

Answer:

x^2+y^2+z^2-10x-6y-10z +50 =0

Step-by-step explanation:

Given that a sphere is contained in the first octant

Centre of the sphere is given as (5,3,5)

Since this is contained only in the first octant radius should be at most sufficient to touch any one of the three coordinate planes

When it touches we can get the maximum sphere

We find that y coordinate is the minimum of 3 thus radius can be atmost 3 so that then only it can touch y =0 plane i.e. zx plane without crossing to go to the other octants.

Hence radius =3

Equation of the sphere would be

$(x-5)^2 +(y-3)^2+(z-5)^2 = 3^2\\x^2+y^2+z^2-10x-6y-10z +50 =0$

8 0

3 years ago

Whats the probability of a five card straight in poker without replacement

Ad libitum [116K]

Answer:

one fifth of a chance

Step-by-step explanation:

6 0

3 years ago