Answer:
3/4 if meant ![a=2,b=4,c=10,d=15](https://tex.z-dn.net/?f=a%3D2%2Cb%3D4%2Cc%3D10%2Cd%3D15)
is ![a^3b^{-2}c^{-1}d](https://tex.z-dn.net/?f=a%5E3b%5E%7B-2%7Dc%5E%7B-1%7Dd)
Step-by-step explanation:
So the expression we want to evaluate for ![a=2,b=4,c=10,d=15](https://tex.z-dn.net/?f=a%3D2%2Cb%3D4%2Cc%3D10%2Cd%3D15)
is ![a^3b^{-2}c^{-1}d](https://tex.z-dn.net/?f=a%5E3b%5E%7B-2%7Dc%5E%7B-1%7Dd)
Please make sure I typed the expression and the values for the letters right.
![a^3b^{-2}c^{-1}d](https://tex.z-dn.net/?f=a%5E3b%5E%7B-2%7Dc%5E%7B-1%7Dd)
Plug in the given values:
![(2)^3(4)^{-2}(10)^{-1}(15)](https://tex.z-dn.net/?f=%282%29%5E3%284%29%5E%7B-2%7D%2810%29%5E%7B-1%7D%2815%29)
In the following step I said 2^3 equals 8 because 2^3 means 2*2*2. I also got rid of the negative exponents by taking reciprocal.
![8 \cdot \frac{1}{4^2} \cdot \frac{1}{10^1} (15)](https://tex.z-dn.net/?f=8%20%5Ccdot%20%5Cfrac%7B1%7D%7B4%5E2%7D%20%5Ccdot%20%5Cfrac%7B1%7D%7B10%5E1%7D%20%2815%29)
In the following step I said 4^2=16 because 4^2 means 4*4. I also wrote 10^1 as 10.
![8 \cdot \frac{1}{16} \cdot \frac{1}{10} (15)](https://tex.z-dn.net/?f=8%20%5Ccdot%20%5Cfrac%7B1%7D%7B16%7D%20%5Ccdot%20%5Cfrac%7B1%7D%7B10%7D%20%2815%29)
In the following step, I'm going to rewrite everything as a fraction if it isn't already a fraction. 8=8/1 and 15=15/1.
![\frac{8}{1} \cdot \frac{1}{16} \cdot \frac{1}{10} \cdot \frac{15}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B1%7D%20%5Ccdot%20%5Cfrac%7B1%7D%7B16%7D%20%5Ccdot%20%5Cfrac%7B1%7D%7B10%7D%20%5Ccdot%20%5Cfrac%7B15%7D%7B1%7D)
To multiply fractions, you just multiply straight across on top and straight across on bottom.
![\frac{8(1)(1)(15)}{1(16)(10)(1)}](https://tex.z-dn.net/?f=%5Cfrac%7B8%281%29%281%29%2815%29%7D%7B1%2816%29%2810%29%281%29%7D)
Actually performing the multiplication:
![\frac{120}{160}](https://tex.z-dn.net/?f=%5Cfrac%7B120%7D%7B160%7D)
Time to reduce:
I divided top and bottom by 10 to get this.
One more time for reducing:
I divided top and bottom by 4 to get this.