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serious [3.7K]
3 years ago
9

Evaluate the expression.

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
8 0

Step-by-step explanation:

for a³b²c-1d

given

a=2

b=4

c=10

d=15

a³b²c-¹d

=(2³4²10^-1*15

=2³4²15/10

=8*16*15/10

=8*8*3

=64*3

=192

now

a³b²c¹d

=(2³4²10 15)

=(8*16*10*15)

=120*16*10

=1200*16

=19200

Kay [80]3 years ago
3 0

Answer:

3/4 if meant a=2,b=4,c=10,d=15

is a^3b^{-2}c^{-1}d

Step-by-step explanation:

So the expression we want to evaluate for a=2,b=4,c=10,d=15

is a^3b^{-2}c^{-1}d

Please make sure I typed the expression and the values for the letters right.

a^3b^{-2}c^{-1}d

Plug in the given values:

(2)^3(4)^{-2}(10)^{-1}(15)

In the following step I said 2^3 equals 8 because 2^3 means 2*2*2.  I also got rid of the negative exponents by taking reciprocal.

8 \cdot \frac{1}{4^2} \cdot \frac{1}{10^1} (15)

In the following step I said 4^2=16 because 4^2 means 4*4.  I also wrote 10^1 as 10.

8 \cdot \frac{1}{16} \cdot \frac{1}{10} (15)

In the following step, I'm going to rewrite everything as a fraction if it isn't already a fraction.  8=8/1 and 15=15/1.

\frac{8}{1} \cdot \frac{1}{16} \cdot \frac{1}{10} \cdot \frac{15}{1}

To multiply fractions, you just multiply straight across on top and straight across on bottom.

\frac{8(1)(1)(15)}{1(16)(10)(1)}

Actually performing the multiplication:

\frac{120}{160}

Time to reduce:

\frac{12}{16} I divided top and bottom by 10 to get this.

One more time for reducing:

\frac{3}{4} I divided top and bottom by 4 to get this.

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9514 1404 393

Answer:

 BC ≈ 17.0 (neither Crow nor Toad is correct)

Step-by-step explanation:

The left-side ratio of (2+4)/4 = 3/2 suggests BC is 3/2 times the length DE. If that were the case, BC = (3/2)(11) = 16.5, as Crow says.

The right-side ratio of (5+9)/9 = 14/9 suggests that BC 9 is 14/9 times the length DE. If that were the case, BC = (14/9)(11) = 154/9 = 17 1/9 ≈ 17.1, as Toad says.

The different ratios of the two sides (3/2 vs 14/9) tell you that the triangles are NOT similar, so the length of BC cannot be found by referring to the ratios of the given sides.

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5 0
3 years ago
4 less than a number n is - 15 as a equation
Nikitich [7]

Answer:

I believe the equation would be n - 2 = -15.

Step-by-step explanation:

"4 less than a number (n)" is subtraction. You can write it as "n minus 4". "is -15" means this is the difference. This can also be written as "equals -15".

n - 4 = -15

Hope this helps,

♥<em>.A.W.E</em><u><em>.S.W.A.N.</em></u>♥

7 0
3 years ago
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I need help with this question
Novay_Z [31]

Answer:

$ \frac{\sqrt{3} - 1}{2\sqrt{2}} $

$ \frac{-(\sqrt{3} + 1)}{2\sqrt{2}} $

$ - \frac{\sqrt{3} - 1}{\sqrt{3} + 1} $

Step-by-step explanation:

Given $ \frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6} $

(A) $ sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4}  + \frac{\pi}{6}) $

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$ sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2} $

$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}

(B) Cos(A + B) = CosAcosB - SinASinB

$ cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}}) $

$ \implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2} $

$ \implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}) $

$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}

(C) Tan(A + B) = $ \frac{Sin(A +B)}{Cos(A + B)} $

From the above obtained values this can be calculated and the value is $ - \frac{\sqrt{3} - 1}{\sqrt{3} + 1} $.

3 0
3 years ago
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