If Pipe 1 (P1) takes x hours to fill the pool, Pipe 2 (P1) and pipe 2 (P2) takes (x-9) hours to fill the pool, and pipe 2 (P2) takes (x+7) hours to fill the pool.
That is,
P1 = x hrs
P1+P2 = (x-9) hrs
P3 = (x+7) hrs
In 1 hour, P1 fills 1/x of the pool, P1+P2 fills 1/(x-9) of the pool and P2 fills 1/(1+7) of the pool.
Therefore,
1/x+1/(1+7) = 1/(x-9) => ((x+7)+x)/(x)(x+7)=1/(x-9) => (2x+7)/x^2+7x = 1/(x-9) => (2x+7)(x-9)=x^2+7x => x^2-18x-63 =0
Solving for x
x= (-b+/- sqrt (b^2-4ac)/2a, where a=1, b=18, and c=63
Substituting;
x1=21 and x2=-3 (the negative x is ignored as it does not make sense).
Therefore, x = 21
This means,
P1 takes 21 hours to fill the pool
P1+P2 takes (21-9) hours = 12 hours to fill the pool while P3 takes (21+7) hours = 28 hours
An equivalent name for the number 96 is word form ninety-six,or 90 + 6
Answer:
2*7 SO 14 A WEEK
Step-by-step explanation:
Answer 1 / 25
Step-by-step explanation:
The probability that the first
of the three mutants will take over the population = 2 / 100
The probability that the second
of the three mutants will take over the population = 1.01 / 100
The probability that the third
of the three mutants will take over the population = 0.99 / 100
Therefore, the probability that each of the three mutants will take over the population = probability of the first,second or third = 2 / 100 + 1.01 / 100 + 0.99 / 100 = (2+1.01+0.99)/100 = 4 / 100 = 2/25
Answer: (0,4)
Step-by-step explanation: Its the point that intrrcepts the y-axis hence the name
