What I would do for this problem, is move all the terms that don't contain m to the right side, and then solve.
m = 4/5.
Answer:
c
Step-by-step explanation:
Given that f(x) = ax – 5 and f(4) = 15, then the value of a is 5
The given function is:
f(x) = ax - 5
If f(4) = 15, then x = 4
Substitute x = 4 into f(x) = ax - 5
f(4) = a(4) - 5
15 = 4a - 5
Solve for a by adding 5 to both sides
15 + 5 = 4a - 5 + 5
20 = 4a
Divide both sides by 4
4a/4 = 20/4
a = 5
Given that f(x) = ax – 5 and f(4) = 15, then the value of a is 5
Learn more on linear functions here: brainly.com/question/15602982
Answer:
Let the sides be a and b
a^2 + b^2 = c^2 = 29^2 = 841
a^2 + (a + 1)^2 = 841
a^2 + a^2 + 2 a + 1 = 841
2 a^2 + 2 a = 840
a (a + 1) = 420
21 * 20 = 420 trial and error
So the sides are 20 and 21
20^2 + 21^2 = 29^2
Answer:
0.8
Step-by-step explanation: