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lora16 [44]
3 years ago
14

(Minimum or maximum), (4, 8, 7, 23.)

Mathematics
2 answers:
lisov135 [29]3 years ago
8 0
8 minimum wage for the year to come round hea again and the
allochka39001 [22]3 years ago
4 0

Answer:

minimum value of 7

Step-by-step explanation:

It is open up so it has a minimum

The minimum value is the lowest y

So we first must find the x that the point happens at which is -b/(2a)

So -(-8)/(2*1)=8/2=4

Now to find the y use y=x^2-8x+23

y=4^2-8(4)+23

y=16-32+23

y=-16+23

y=7  (lowest y-minimum value is 7)

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JK in the coordinate plane has endpoints with coordinates (-4, 11) and (8,
atroni [7]

Answer:

(0, 7)

Step-by-step explanation:

Given:

J(-4, 11)

K(8, -1)

JP:JK = 1/3

Required:

Coordinates of P

SOLUTION:

Use the formula, (x, y) = (x_1 + k(x_2 - x_1), y_1 + k(y_2 - y_1)) to find the coordinates of point P, that partition the segment JK into the ratio 1/3.

Let,

J(-4, 11) = (x_1, y_1)

K(8, -1) = (x_2, y_2)

k = \frac{1}{3}

Thus, plug in the values as follows:

P(x, y) = (-4 + \frac{1}{3}(8 -(-4)), 11 + \frac{1}{3}(-1 - 11)

P(x, y) = (-4 + \frac{1}{3}(12), 11 + \frac{1}{3}(-12)

P(x, y) = (-4 + \frac{12}{3}, 11 + \frac{-12}{3})

P(x, y) = (-4 + 4,  11 + (-4)

P(x, y) = (0, 7)

The coordinates of point P, are (0, 7)

3 0
3 years ago
The monthly sales (in thousands of units) of a seasonal product are approximated by
Elodia [21]
 <span>Don't forget S is measured in thousands of units so you are solving for : 

100 < 74.5 + 43.75Sin(πt/6) 
25.5 < 43.75Sin(πt/6) 
Sin(πt/6) >25.5/43.75 = 0.582857 
ASrcSin(πt/6) > 0.62224 radians 
πt/6 > 0.62224 
t > 6 x 0.62224/π = 1.1884 (4dp) 

This initial value occurs when the sine value is increasing and it will reach its maximum value of 1 when Sin(πt/6) = Sinπ/2, that is when t = 3. 
Consequently, monthly sales exceed 100,000 during the period between t = 1.1884 and 4.8116 
[3 - 1.1884 = 1.8116 so the other extreme occurs at 3 + 1.8116] 

Note : on the basis of these calculations, January is 0 ≤ t < 1 : February is 1 ≤ t < 2 :....May is 4 ≤ t < 5 
So the period when sales exceed 100,000 occurs between Feb 6 and May 25 and annually thereafter.</span>
3 0
3 years ago
What is 420 centimeters to meter
Ronch [10]

Here is the best answerrrrr.

8 0
3 years ago
Read 2 more answers
Help! Urgent request
TiliK225 [7]

Answer: 6 students

What we know:

Students: 24

Students who play checkers: \frac{2}{3}

Students who also play sudoku:\frac{3}{8} of the \frac{2}{3}

24 ÷ 3 = 8, so 8 × 2 = 16 (students who play checkers)

\frac{3}{8} × 2 = \frac{6}{16}

So the answer is,

6 students play both checkers and sudoku

8 0
3 years ago
Read 2 more answers
Classify each sequence as arithmetic, geometric or neither
Karolina [17]

Answer:

Geometric sequence = ⁵/9, ⁵/3, 5, 15, 45. . .

Arithmetic sequence = 16, 11, 6, 1, -4 . . .

Step-by-step explanation:

A geometric sequence is a sequence of numbers, in which every number in the sequence after the first term is multiplied by a common ratio, which gives us the next term. The common ratio is the ratio of a term to the term before it.

On the other hand, an arithmetic sequence is a sequence of number have a common difference between each consecutive terms. This common difference is gotten by subtracting a term from the term before it.

Now let's examine each sequence given:

==>16, 11, 6, 1, -4 . . .

11 - 16 = -5

6 - 11 = -5

1 - 6 = -5

-4 - 1 = -5

This is an arithmetic sequence. The commons difference "-5" is the same

==>⁵/9, ⁵/3, 5, 15, 45. . .

⁵/3 ÷ ⁵/9 = ⁵/3 × ⁹/5 = ⁹/3 = 3

5 ÷ ⁵/3 = ⁵ × ⅗ = 3

15 ÷ 5 = 3

45 ÷ 15 = 3

The common ratio "3" is the same. This is a geometric sequence.

3 0
2 years ago
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