All categories

3 years ago

Working out simultaneous equations.

Mathematics

1 answer:

KiRa [710]3 years ago

5 0

Answer:

x = 6/5

y = 8/5

Step-by-step explanation:

3x - y = 2

2x + y = 4

Add the equations, cancelling y.

5x = 6

x = 6/5

Put x as 6/5 in the second equation and solve for y.

2(6/5) + y = 4

12/5 + y = 4

y = 4 - 12/5

y = 8/5

You might be interested in

Given mn, find the value of x.

Lesechka [4]

Answer:

x = 23

Step-by-step explanation:

You have to find where they are equal because the angle will be the same.

8x - 27 = 7x + 4

x = 23

4 0

3 years ago

Read 2 more answers

Jasmine tossed a coin in the air. what is the probability the coin will land on tails?

katrin2010 [14]

Answer: equally likely

Step-by-step explanation: I have a coin. My coin has 2 sides. I have a 50 percent chance of landing on ether side so equally likely.

4 0

3 years ago

Read 2 more answers

1.) Using appropriate properties find. -2/3×3/5+5/2-3/5×1/6

frez [133]

Answer:

Step-by-step explanation:

Multiply then add

4 0

3 years ago

What is the solution for x in the given equation? The square root of 9x +7 + the square root of 2x = 7

cestrela7 [59]

Answer:

The solution is x =2 for the given equation $\sqrt{9x+7} +\sqrt{2x}=7$

Step-by-step explanation:

We need to find the solution for x in the given equation.

$\sqrt{9x+7} +\sqrt{2x}=7$

Solving:

Subtract $\sqrt{2x}$ from both sides

$\sqrt{9x+7} =7-\sqrt{2x}$

Taking square on both sides

$(\sqrt{9x+7})^2 =(7-\sqrt{2x})^2\\Using\,\, (a-b)^2 = a^2-2ab-b^2\\9x+7=(7)^2-2(7)(\sqrt{2x})+(\sqrt{2x})^2\\9x+7=49-14\sqrt{2x}+2x\\9x-2x+7-49=-14\sqrt{2x}\\7x-42=-14\sqrt{2x}\\Taking\,\,square\,\,on\,\,both\,\,sides\\(7x-42)^2=(-14\sqrt{2x})^2\\49x^2-2(7x)(42)+(42)^2= 196(2x)\\49x^2-588x+1764=392x\\49x^2-588x+1764-392x=0\\49x^2-980x+1764=0\\Using \,\,quadratic \,\, equation \,\,to \,\, find \,\, value \,\, of \,\, x \\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a= 49, \, b= -980 \,\,and\,\, c = 1764$