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2 years ago

What is the mean of 3,4.5,6.5,8,8.5,10

1 answer:

8 0

Finding the mean is just the fancy way of saying to find the average of something. To find the average, all you need to do is add up all the numbers then divide by the amount of numbers.

3+4.5+6.5+8+8.5+10 / 7 = 6.75

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tina drove 60 miles per hour to tucson. write a function rule that relates the number of miles traveled to the total of the hour

just olya [345]

A function rule would be y = 60x. Y represents the number of miles traveled, and X represents the number of hours. For example, if Tina drove for three hours, it would be 60×3 which is 180 miles.

5 0

2 years ago

(a^(2)-4ac+3bc)/(a^(2)-ab+bc-ac)+(a+3b)/(b-a)+(a+2c)/(a-c)

Bingel [31]

Answer:

The answer is −a^4 + 5a^3b + 2a^3c − 4a^2b^2 − 10a^2bc − a^2c^2 + 8ab^2c + 5abc^2 − 4b^2c^2 / −a^4 + 2a^3b + 2a^3c − a^2b^2 − 4a^2bc − a^2c^2 + 2ab^2c + 2abc^2 − b^2c^2

Step-by-step explanation:

This the equation being simplified

4 0

2 years ago

Read 2 more answers

You bought a car that was $25500 and the value depreciates by 4.5% each year.

nikklg [1K]

Answer:

(a) 20256.15625

(b) 17642.78546

Step-by-step explanation:

(a) There's a formula for this problem y = A(d)^t where, A is the initial value you are given, d is the growth or decay rate and t is the time period. So, in this case, as the car cost is decreasing it is a decay problem and we can write the formula as such; y = A(1-R)^t

So, in 5 years the car will be worth, 25500(1-4.5%)^5 or 20256.15625 dollars

(b) And after 8 years the car will be worth 25500(1-4.5%)^8 or 17642.78546 dollars.

7 0

2 years ago

Me trying to pass test

user100 [1]

Answer:

Step-by-step explanation:

b is the answer to your test

6 0

3 years ago

Read 2 more answers

Traveling math word problem - thank you! :)

Anni [7]

We are given:

car and train leave at the same time

average velocity of car = 50 miles/hour

average velocity of train = 70 miles/hour

train arrives 2 hours early

Assuming variables and making equations!

let the time taken by the train = t hours

since the car arrived late, it took more time as compared to the train

time taken by the car = t + 2 hours

since the distance from Pasadena to Sacramento doesn't change, both the vehicles covered the same distance, d

Distance travelled by the car:

d = 50 $\frac{miles}{hour}$ * (t+2) hours [distance = velocity * time]

d = 50(t+2) miles

rewriting in terms of t

$t = \frac{d-100}{50}$

Distance travelled by the train:

d = 70 $\frac{miles}{hour}$ * t hours

d = 70t miles

rewriting in terms of t

$t = \frac{d}{70}$

now we have two expressions for t, both of which are equal because t is just the time taken by the train

Finding the distance:

$t = \frac{d-100}{50}$

$t = \frac{d}{70}$

because t is the same:

$\frac{d-100}{50} = \frac{d}{70}$

$\frac{d-100}{5} = \frac{d}{7}$

7(d - 100) = 5(d)

7d - 700 = 5d

(7d - 5d) - 700 = 0 [subtracting 5d from both sides]

2d = 700 [adding 700 on both sides]

d = 350 miles [dividing both sides by 2]

The distance between Pasadena and Sacramento is 350 miles!

7 0

1 year ago