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3 years ago

What is the median of 1.99 2.99 3.89 3.99

2 answers:

5 0

Normally you would put the numbers least to greatest and the number in the middle would be the median.
But in this case 2 numbers, 2.99 and 3.89 are in the middle.
In this case the mean of the two middle numbers is the median.
3.44

mash [69]3 years ago

5 0

Median is the middle number, since these are already aligned in least to greatest, we could find it easily.

Between 2.99 and 3.89 is 3.44

Answer: 3.44

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EASY 7TH GRADE MATH, WILL GIVE BRAINLIEST AND THANKS

Fudgin [204]

Answer:

D. 8

Step-by-step explanation:

2p=16

divide both sides by 2 to get p alone

p=8

7 0

2 years ago

Read 2 more answers

Given the equation (x+a)^2(x-2)=x^3+bx^2+12x-72 find a and b

GaryK [48]

Isolate the variable by dividing each side by factors that don't contain the variable.

$a=- \frac{ x^{2}- \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,- \frac{ x^{2}+ \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}$

Solve for b by simplifying both sides of the equation then isolating the variabel.

$b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }$

Hopefully i helped ^.^ Mark brainly if possible

7 0

3 years ago

What is true about anglemsr? it must be acute. it must be a right angle. it must be equal to anglemrh. it must be equal to angle

NARA [144]

From the given diagram <msr is a right angle (equal to 90 degrees) and <mrh is acute since it is less than 90degrees.

<h3>Properties ofa rhombus</h3>

The given diagram is a rhombus that has the following properties

Opposite side are equal
All the sides are congruent
The opposite angles are equal
The sum of the adjacent angles are supplementary

From the figure shown, we can see that;

<msr is a right angle (equal to 90 degrees)

<mrh is acute since it is less than 90degrees.

Learn more on rhombus here: brainly.com/question/88523

#SPJ1

7 0

2 years ago

Help if you can do this please

olga nikolaevna [1]

Answer:

Step-by-step explanation:

a. Since the parabola is compressed by a factor of 1/3 we can state:

a parabola is written this way : y=(x-h)²+k
h stands for the translation to the left ⇒ 2*3=6
k for the units down ⇒4*3=12

So the equation is : y=(x-6)²+12

b.Here the parabola is stretched by a factor of 2 so we must multiply by 1/2

We khow that a parabola is written this way : y=(x-h)²+k
(h,k) are the coordinates of the vertex
the maximum value is 7*0.5=3.5
we khow tha the derivative of a quadratic function is null in the maximum value
so let's derivate (x-h)²+k= x²+h²-2xh+k
f'(x)= 2x-2h h is 1 since the axe of simmetry is x=1
f'(x)=2x-2 ⇒2x-2=0⇒ x= 1
Now we khow that 1 is the point where the derivative is null
f(1)=3.5
3.5=(x-1)²+k
3.5= (1-1)²+k⇒ k=3.5

So the equation is : y=(x-1)²+3.5

the maximum height is where the derivative equals 0

h= -5.25(t-4)²+86
h= -5.25(t²-8t+16)+86
h=-5.25t²+42t-84+86
h=-5.25t²+42t+2

Let's derivate it :

f(x)= -10.5t+42
-10.5t+42=0
42=10.5t
t= 42/10.5=4

When the height was at max t=4s

h(max)= -5.25(4-4)²+86 = 86 m

h was 86m

8 0

2 years ago

What is the measure of angle B in the figure below?

gizmo_the_mogwai [7]

Answer:

It's 45 degrees on edgen

Step-by-step explanation:

and whichever dumb b&tch deleted my comment, please stop riding my d&ck so hard<3 thanks

7 0

3 years ago