Question

Consider a mass-spring system. The spring has a spring constant 2.17e 3 N/m. On the end is a mass of 4.71 kg. You start at equilibrium with an initial velocity of 1.78 m/s. What is the maximum displacement

Answer 1

Answer:

7.4 cm

Explanation:

K = 2.17 x 10^3 N/m

m = 4.71 kg

v = 1.78 m/s (It is maximum velocity)

The angular velocity

$\omega =\sqrt{\frac{k}{m}}$

$\omega =\sqrt{\frac{2.71\times 10^{3}}{4.71}}$

ω = 24 rad/s

Maximum velocity, v = ω x A

Where, A be the maximum displacement

1.78 = 24 x A

A = 0.074 m = 7.4 cm