A circular loop of wire with ra dius 8.0 cm carries a current of 0.20 A. A vec- tor of unit length and parallel to the dipole mo
- ment ii of the loop is 0.60i 0.80j. If the loop is located in a uniform magnetic field given by B (0.25T) (0.30T)k, what is the orientation energy of the loop? a) 0 J b) -6.0 x 10-4 J c) 2.5 x 10-4 J d) 3.2 x 10-4 J e) 5.1 x 10-3 J
1 answer:
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Answer:
2.1 × 10⁻⁵ T
Explanation:
Given:
Inner radius, r = 4 mm = 0.004 m
Outer radius, R = 25 mm = 0.025 m
Current, I = 4 A
Distance of the point from the center, a = 17 mm = 0.017 m
μ₀ = 4π × 10⁻⁷ T·m/A
Now,
For the hollow cylinder magnetic field (B) is given as:
on substituting the respective values, we get
or
B = 2.1 × 10⁻⁵ T