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3 years ago

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A circular loop of wire with ra dius 8.0 cm carries a current of 0.20 A. A vec- tor of unit length and parallel to the dipole mo

- ment ii of the loop is 0.60i 0.80j. If the loop is located in a uniform magnetic field given by B (0.25T) (0.30T)k, what is the orientation energy of the loop? a) 0 J b) -6.0 x 10-4 J c) 2.5 x 10-4 J d) 3.2 x 10-4 J e) 5.1 x 10-3 J

1 answer:

Sauron [17]3 years ago

3 0

Answer:

B= -6.0×10⁻⁴J

Explanation:

FIND THE SOLUTION BELOW

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$\purple{\maltese}\large\underline{\underline{\sf\:\: Given :}} \\$

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$\\\purple{\maltese}\large\underline{\underline{\sf\:\: To \: \: Find :}} \\$

» The height of the Building= ??

$\\\purple{\maltese}\large\underline{\underline{\sf\:\: Solution :}} \\ \\$

★ <u>Height of the </u><u>building </u><u>by the principal of conservatio</u>n;

$\\\\\begin{gathered}\purple{\maltese}\large\underline{\underline{\sf\:\: using \: formula :}} \\ \\\end{gathered}$

$\bigstar \: \underline{ \boxed{\sf { \pink{ \: \frac{1}{2} \: \: mv { }^{2} = \: mgh \: }}}}$

$\\ \: \: \underline{\textsf {Putting values \: in \: the \: \: given \: formula :}} \\$

$\\ \sf \implies \: \frac{1}{2} \: \: mv { }^{2} = \: mgh \: \\$

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