Emily designed a robot that could climb down steps. She drew a graph to show the results from a test of her new robot. The graph
shows the number of steps remaining over time.
What is the equation that represents Emily’s situation?
A. y=−1/10x+15
B. y = 10x + 150
C. y=−10x+150
D. y=1/10x+15
What is the equation that represents Emily’s situation?
A. y=−1/10x+15
B. y = 10x + 150
C. y=−10x+150
D. y=1/10x+15
2 answers:
The answer is A.) 
To find this answer the first thing we need to do is look at the equation of a straight line: y=mx+b
What I did first was look at b. b represents the y-intercept. By looking at the graph we can tell that the line crosses the y-axis at (0,15), so the y- intercept is 15. So our answer should at least have b=15. Using this we can go ahead and eliminate answers B & C
Next we look at the slope (m). One way you can figure out slope is using the rise over run method. Since this line has a negative slope our rise should be a negative number. So, the only answer that should be left is A.)
To find this answer the first thing we need to do is look at the equation of a straight line: y=mx+b
What I did first was look at b. b represents the y-intercept. By looking at the graph we can tell that the line crosses the y-axis at (0,15), so the y- intercept is 15. So our answer should at least have b=15. Using this we can go ahead and eliminate answers B & C
Next we look at the slope (m). One way you can figure out slope is using the rise over run method. Since this line has a negative slope our rise should be a negative number. So, the only answer that should be left is A.)
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The frustum can be considered as consisting of a square pyramid, less the
cut volume.
- The mass of the stand, is approximately 18.60905 kg
Reasons:
The given parameter of the frustum are;
The density of the frustum, ρ = 85 g/cm³
Height of pyramid, h = 9 cm
Side length of base = 10 cm
Height of frustum
By proportional shapes, the side length of the top of the frustum can be found as follows;
B₁ = 10², B₂ =
Therefore;
The volume of the stand, V ≈ 218.93 cm³
Mass = Volume × Density
∴ Mass of the stand, m = 218.93 cm³ × 85 g/cm³ = 18,609.05 grams = 18.60905 kg.
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