Answer:
b = 7
Step-by-step explanation:
108 = -2(-5 - 7b)
Distribute -2 to the terms inside the parenthesis:
108 = 10 + 14b
Subtract 10 from both sides of the equation to isolate 14b:
108 - 10 = 10 + 14b - 10
98 = 14b
Divide 14 on both sides of the equation to solve for b:

7 = b
Answer:
Hence, the relation R is a reflexive, symmetric and transitive relation.
Given :
A be the set of all lines in the plane and R is a relation on set A.

To find :
Which type of relation R on set A.
Explanation :
A relation R on a set A is called reflexive relation if every
then
.
So, the relation R is a reflexive relation because a line always parallels to itself.
A relation R on a set A is called Symmetric relation if
then
for all
.
So, the relation R is a symmetric relation because if a line
is parallel to the line
the always the line
is parallel to the line
.
A relation R on a set A is called transitive relation if
and
then
for all
.
So, the relation R is a transitive relation because if a line
s parallel to the line
and the line
is parallel to the line
then the always line
is parallel to the line
.
Therefore the relation R is a reflexive, symmetric and transitive relation.
9514 1404 393
Answer:
3
Step-by-step explanation:
For f(x) = x^3 -2x^2 -7x +5 and x=1/(2-√3), we have ...
f(x) = ((x -2)x -7)x +5
and ...
x = 1/(2-√3) = (2+√3)/(2^2 -3) = 2+√3
Then ...
f(2+√3) = ((2 +√3 -2)(2 +√3) -7)(2 +√3) +5
= (3+2√3 -7)(2+√3) +5
= 2(√3 -2)(√3 +2) +5 = 2(3 -4) +5 = -2 +5
f(1/(2 -√3)) = 3
_____
If you really mean x = (1/2) -√3, then f(x) = (42√3 -3)/8.