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Alisiya [41]
3 years ago
7

What is the fraction if you have $.95 And for the coins are twice as much as the rest how can I construct a Mac argument could j

ustify and for the coins are twice as much as the rest how can I construct a math argument to justify the conjecture of 11 nickels and 4 dimes
Mathematics
1 answer:
DaniilM [7]3 years ago
6 0
I really need five points
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Suppose SAT Writing scores are normally distributed with a mean of 488488 and a standard deviation of 111111. A university plans
makvit [3.9K]

Answer:

The minimum score required for the scholarship is 644.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 488, \sigma = 111

What is the minimum score required for the scholarship?

Top 8%, which means that the minimum score is the 100-8 = 92th percentile, which is X when Z has a pvalue of 0.92. So it is X when Z = 1.405.

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 488}{111}

X - 488 = 1.405*111

X = 644

The minimum score required for the scholarship is 644.

4 0
3 years ago
Plz guys help I need help
Lunna [17]
The answer would be 56 pounds
5 0
3 years ago
Read 2 more answers
I will give you a Brainly crown if it is right. Will you help me
NISA [10]

Answer:

Right angles are 90 degrees.

The A is 5 degrees so we subtract that off

85 degrees is the answer

Step-by-step explanation:

5 0
3 years ago
4) Solve ∆ABC, a = 2.5 cm, c = 3.6 cm, and ∠A = 43°. Begin by sketching and labelling
mezya [45]

The length of b and angle B and C are 3cm, 45  degrees and 79 degrees respectively.

<h3>How to determine the parameters</h3>

To determine the angles and length of sides, we use the sine rule

The sine rule is thus:

\frac{sin A}{a} = \frac{sin B}{b} = \frac{sin C}{c}

Given;

  • a = 2. 5cm
  • c = 3. 6cm
  • ∠A = 43°

Let's find angle C

\frac{sin 43}{2. 5} = \frac{sin C}{3. 6}

cross multiply

0. 682 × 3. 6 = sin C × 2. 5

sin C = 2. 4552/ 2. 5

C = sin^-^1(0. 982)

C = 79°

To find length of b

b= \sqrt{c^2 - a^2}

substitute the values

b = \sqrt{3.6^2 - 2. 5^2}

b = \sqrt{6. 71}

b = 2. 59 cm

b = 3cm

To find angle B, we have

\frac{sin 43}{2. 5} = \frac{sin B}{2. 59}

cross multiply

0. 682 × 2. 59= sin B × 2. 5

sin B = 0. 7065

B = sin^-^1(0. 7065)

B = 45°

Hence, the length of b and angle B and C are 3cm, 45  degrees and 79 degrees respectively.

Learn more about sine rule here:

brainly.com/question/12827625

#SPJ1

8 0
2 years ago
Simplify radicals problems attached please help!
Finger [1]

Answer:

  G7.  (2√3)/3

  G8.  -2+√7

  G9.  (6 +2√2 -3√3 -√6)/7

Step-by-step explanation:

G7.

\dfrac{2}{\sqrt{3}}=\dfrac{2}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{2\sqrt{3}}{3}

__

G8.

\dfrac{3}{2 +\sqrt{7}}=\dfrac{3}{2+\sqrt{7}}\cdot\dfrac{2-\sqrt{7}}{2-\sqrt{7}}=\dfrac{6-3\sqrt{7}}{2^2-(\sqrt{7})^2}\\\\=\dfrac{6-3\sqrt{7}}{-3}=\sqrt{7}-2

__

G9.

\dfrac{2-\sqrt{3}}{3-\sqrt{2}}=\dfrac{2-\sqrt{3}}{3-\sqrt{2}}\cdot\dfrac{3+\sqrt{2}}{3+\sqrt{2}}=\dfrac{(2-\sqrt{3})(3+\sqrt{2})}{9-2}\\\\=\dfrac{6+2\sqrt{2}-3\sqrt{3}-\sqrt{6}}{7}

_____

<em>Comment on the problems</em>

In most cases, these expressions are the simplest possible (take the least amount of ink to draw, and take the fewest math operations to evaluate). What seems to be intended is that the denominator be made a rational number. This is done by multiplying the given fraction by a fraction equal to 1 that has the same denominator but with the sign of the radical reversed (unless, as in the first case, the radical is by itself).

The purpose of doing this is to take advantage of the fact that (a-b)(a+b) = a²-b², so if "a" or "b" is a square root, that root will not be seen in the product. In problem G9, we see this can make the numerator quite messy--not exactly a simpler form--but all the irrational numbers are in the numerator.

8 0
3 years ago
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