Answer:
Answer in explanation below!
Explanation:
I used a punnett square to figure this out!
phenotypic ratio ( meaning how it will look ) = 1 : 1 ( Gg = 50% & gg = 50% )
genotypic ratio ( the allele combo ) = 1 : 1 ( Gg = 50% & gg = 50% )
I hope this helps, good luck!
Assuming Hardy-Weinberg equilbrium, we have
p + q = 1
where p = frequency of dominant allele and q = frequency of recessive allele. So
p = 1 - q = 1 - 0.04 = 0.96
Consequently we have
• p² = 0.9216 = frequency of hom ozygous domininant genotype
• pq = 0.0768 = frequency of heterozygous genotype
• q² = 0.0016 = frequency of hom ozygous recessive genotype
since
p² + 2pq + q² = 1
Answer:
Areas where the air is warmed often have lower pressure because the warm air rises. These areas are called low pressure systems. Places where the air pressure is high, are called high pressure systems. A low pressure system has lower pressure at its center than the areas around it.
Explanation:
Mark brainiest'
To test his hypothesis, the student will have to design an experiment to measure the effects of <u>temperature on cellular growth</u>.
To test the effects of temperature on cellular growth the student will have to create an experiment containing the there kinds of variables:
- Dependent
- Independent
- Control
In this experiment, the control variable will be the kind of cells used, as well as the incubation methods being used. We identify these as the control variable given that they will remain constant.
The independent variable will be the Temperature at which we will place each cell being studied. The dependent variable, on the other hand, is by definition, what we seek to measure. In the case given it would correspond to the amount of cellular growth.
To test his theory of the effects of temperature on cellular growth, a student can design an experiment in which the control variable will be the cells themselves, the independent variable will be the Temperature, and the cellular growth can act as the dependent variable.
To learn more:
brainly.com/question/9199868?referrer=searchResults
Long ears have to be dominant:
If this IS true then these would be your 'parents':
L = long ears
l = curly ears
LL x ll
If you cross the homozygous recessive curly eared rabbit (ll) with homozygous dominant long eared rabbit (LL) you would get 100% Ll - all would look long eared.